XDocument.load(string uri) throws ArgumentNullException
本文关键字:throws ArgumentNullException uri string load XDocument | 更新日期: 2023-09-27 17:54:36
我得到一个ArgumentNullException时调用
string filepath = @"AppData'TestAppData.xml";
if (filepath != null)
{
XDocument xdoc = XDocument.Load(filepath);
}
下面是异常的详细信息。它说,"格式"参数是空的-但在什么时候我能够控制这个参数?或者我到底错在哪里?
> System.ArgumentNullException was unhandled by user code
> HResult=-2147467261
> Message=Value cannot be null.
> Parameter name: format
> ParamName=format
> Source=mscorlib
> StackTrace:
> at System.String.FormatHelper(IFormatProvider provider, String format, ParamsArray args)
> at System.String.Format(String format, Object[] args)
> at System.SR.Format(String resourceFormat, Object[] args)
> at System.Xml.XmlException.CreateMessage(String res, String[] args, Int32 lineNumber, Int32 linePosition)
> at System.Xml.XmlException..ctor(String res, String[] args, Exception innerException, Int32 lineNumber, Int32 linePosition, String
> sourceUri)
> at System.Xml.XmlTextReaderImpl.Throw(String res, String arg)
> at System.Xml.XmlTextReaderImpl.ParseAttributeValueSlow(Int32 curPos, Char quoteChar, NodeData attr)
> at System.Xml.XmlTextReaderImpl.ParseAttributes()
> at System.Xml.XmlTextReaderImpl.ParseElement()
> at System.Xml.XmlTextReaderImpl.ParseElementContent()
> at System.Xml.XmlTextReaderImpl.Read()
> at System.Xml.Linq.XContainer.ReadContentFrom(XmlReader r)
> at System.Xml.Linq.XContainer.ReadContentFrom(XmlReader r, LoadOptions o)
> at System.Xml.Linq.XDocument.Load(XmlReader reader, LoadOptions options)
> at System.Xml.Linq.XDocument.Load(String uri, LoadOptions options)
> at System.Xml.Linq.XDocument.Load(String uri)
你需要这个
string EnviromentPath = Path.GetDirectoryName(HostingEnvironment.ApplicationPhysicalPath);
获取项目目录的路径然后你应该在
之后组合它们Path.Combine(EnviromentPath,@"AppData'TestAppData.xml");
看一下这个:我如何使用XDocument.Load()在应用程序目录
中获取文件文件路径似乎不正确,试试这个
XDocument xdoc = XDocument.Load(filepath);