从资源加载.dic和.aff文件

本文关键字：aff 文件 dic 资源 加载 | 更新日期: 2023-09-27 18:28:10

要加载.dic和.aff文件，我们使用以下代码。

 using (var hunspell = new Hunspell("en.aff", "en.dic"))
                {
                }

但是，如果使用c#作为资源嵌入，我如何加载NHunsell.dic和.aff文件？

我正在尝试下面的代码，但速度太慢了。

using (var hunspell = new Hunspell(GetBytes(Properties.Resources.enaff), GetBytes(Properties.Resources.endic)))
                {
                }
static byte[] GetBytes(string str)
    {
        byte[] bytes = new byte[str.Length * sizeof(char)];
        System.Buffer.BlockCopy(str.ToCharArray(), 0, bytes, 0, bytes.Length);
        return bytes;
    }

从资源加载.dic和.aff文件

假设您的一个应用程序集中有两个文件作为嵌入资源，例如：

  • 程序集名称：MyApp.MyAssemblyWithResources
  • 的资源名称aff文件：MyApp.MyAssemblyWithResources.AffFile
  • 的资源名称dict文件：MyApp.MyAssemblyWithResources.DictFile

然后要加载并使用它们，请执行以下操作：

// These buffers will receive the content of the embedded resource files.
byte[] affFileBytes = null;
byte[] dictFileBytes = null;
// We have to load the resource files from the assembly in which they were embedded.
var myAssembly = AppDomain.CurrentDomain.GetAssemblies().Where(a => a.FullName.Equals("MyApp.MyAssemblyWithResources")).Single();
// To do so we need to get a stream that allows us to read them.
using (var affResourceStream = myAssembly.GetManifestResourceStream("MyApp.MyAssemblyWithResources.AffFile"))
using (var dictResourceStream = myAssembly.GetManifestResourceStream("MyApp.MyAssemblyWithResources.DictFile"))
{
    // Now we know their size and can allocate room for the buffer.
    affFileBytes = new byte[affResourceStream.Length];
    // And read them from the resource stream into the buffer.
    affResourceStream.Read(affFileBytes, 0, affFileBytes.Length);
    // Same thing for the dictionary file.
    dictFileBytes = new byte[dictResourceStream.Length];
    dictResourceStream.Read(dictFileBytes, 0, dictFileBytes.Length);
}
// Now the loaded buffers can be used for the NHunspell instance.
using (var hunspell = new Hunspell(affFileBytes, dictFileBytes))
{
    // Do stuff with spellin and gramma.
}
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