Messagebox将不会停止显示
本文关键字:显示 Messagebox | 更新日期: 2023-09-27 18:28:13
我正在尝试编写此代码,以便当单击从"FORM1"
启动Obj时,将调用此方法来使用并启用timer1
。
当我点击开始按钮时,狗的图片将开始向右移动,直到到达X= 620
,然后它将显示消息框" win"
然而,在dogpic到达目标线后,消息框一直显示并没有停止
class dog
{
public int startpost;
public int TrackLenght = 620;
public PictureBox dogpic = null;
public int Location = 0;
public Random random=new Random();
public void ResetStart()
{
dogpic.Location = new System.Drawing.Point(40, startpost);
}
public bool testrun()
{
Point p = dogpic.Location;
if (p.X < TrackLenght)
{
int distance = random.Next(5);
p.X = p.X + distance;
dogpic.Location = p;
Location = dogpic.Location.X;
return false;
}
else
{
MessageBox.Show(dogpic.Name + " win");
return true;
}
}
}
//suppose dog1 is an instance of your dog class
//here is the Tick event handler of your timer1
private void timer1_Tick(object sender, EventArgs e){
timer1.Enable = !dog1.testrun();
}
获胜后尝试重新设置p.X。
不要把它看作你的代码,但我认为你应该这样做:
public bool testrun()
{
Point p = dogpic.Location;
if (p.X < TrackLenght)
{
int distance = random.Next(5);
p.X = p.X + distance;
dogpic.Location = p;
Location = dogpic.Location.X;
return false;
}
else
{
MessageBox.Show(dogpic.Name + " win");
ResetStart()
return true;
}}}
点击按钮时,您应该调用ResetStart()函数,该函数将启用计时器并完成您的工作,到达终点时,它应该禁用计时器。
class dog
{
public int startpost;
public int TrackLenght = 620;
public PictureBox dogpic = null;
public int Location = 0;
public Random random=new Random();
public void ResetStart()
{
dogpic.Location = new System.Drawing.Point(40, startpost);
timer.Enabled=true;
}
public bool testrun()
{
Point p = dogpic.Location;
if (p.X < TrackLenght)
{
int distance = random.Next(5);
p.X = p.X + distance;
dogpic.Location = p;
Location = dogpic.Location.X;
return false;
}
else
{
MessageBox.Show(dogpic.Name + " win");
timer.Enabled=false;
return true;
}
}
}
希望它能起作用。
您可以使用计时器。
timer.Interval=5000;
timer.Enabled=true;
MessageBox.Show(dogpic.Name + " win");
您可以将它与tck事件关联起来。
private void timer_Tick(object sender,EventArgs evt) {
timer.Enabled=false;
}