如何使用多个方法调用创建ExpressionTree
本文关键字:调用 创建 ExpressionTree 方法 何使用 | 更新日期: 2023-09-27 18:28:14
我目前有以下代码,可以调用对象的EmailAddress
属性所需的任何方法,而且效果很好:
public static Expression<Func<T, bool>> BuildEmailAddressLambda(string method, params object[] args) {
var e = Expression.Parameter(typeof(T), "e");
var propertyInfo = typeof(T).GetProperty("EmailAddress");
var m = Expression.MakeMemberAccess(e, propertyInfo);
var mi = m.Type.GetMethod(method, args.Select(a => a.GetType()).ToArray());
var c = args.Select(a => Expression.Constant(a, a.GetType())).ToArray();
Expression<Func<T, bool>> lambda = Expression.Lambda<Func<T, bool>>(Expression.Call(m, mi, c), e);
return lambda;
}
// called:
lambda = LambdaExpressionHelper<MailingListMember>.BuildEmailAddressLambda("StartsWith", "r", StringComparison.OrdinalIgnoreCase);
但是,我现在需要修改代码,以便它适用于除EmailAddress
之外的对象成员。具体来说,我想创建一个树来覆盖以下表达式,其中使用了多个方法调用:
e.GetStringValue(12).StartsWith("r", StringComparison.OrdinalIgnoreCase);
我做了几次尝试,但都以各种错误告终。我觉得我在ExpressionTrees的创建逻辑中遗漏了一些东西,如果能提供一些帮助,我将不胜感激。
感谢
这对你有好处吗?
public static Expression<Func<T, bool>> BuildEmailAddressLambda<T>(
string member, IEnumerable<object> memberArgs, string method, params object[] args)
{
var e = Expression.Parameter(typeof(T), "e");
var memberInfo =
(MemberInfo) typeof(T).GetField(member) ??
(MemberInfo) typeof(T).GetProperty(member) ??
(MemberInfo) typeof(T).GetMethod(member, (memberArgs ?? Enumerable.Empty<object>()).Select(p => p.GetType()).ToArray());
Expression m;
if (memberInfo.MemberType == MemberTypes.Method)
{
var a = memberArgs.Select(p => Expression.Constant(p));
m = Expression.Call(e, (MethodInfo) memberInfo, a);
}
else
{
m = Expression.MakeMemberAccess(e, memberInfo);
}
var mi = m.Type.GetMethod(method, args.Select(a => a.GetType()).ToArray());
var c = args.Select(a => Expression.Constant(a, a.GetType()));
return Expression.Lambda<Func<T, bool>>(Expression.Call(m, mi, c), e);
}
// called:
lambda = LambdaExpressionHelper<MailingListMember>.BuildEmailAddressLambda("EmailAddress", null, "StartsWith", "r", StringComparison.OrdinalIgnoreCase);
// or
lambda = LambdaExpressionHelper<MailingListMember>.BuildEmailAddressLambda("GetStringValue", new object[] { 12 }, "StartsWith", "r", StringComparison.OrdinalIgnoreCase);