C64加载屏幕想法
本文关键字:屏幕 加载 C64 | 更新日期: 2023-09-27 18:29:38
我制作了一个加载屏幕(启动屏幕),就像旧的C64一样。
我使用了一系列图片框,只需使用计时器和案例说明更改彩色图像。
switch (a)
{
case 1:
pictureBox1.Image = Properties.Resources.image1;
pictureBox8.Image = Properties.Resources.image1;
pictureBox10.Image = Properties.Resources.image1;
pictureBox2.Image = Properties.Resources.image1;
pictureBox11.Image = Properties.Resources.image1;
pictureBox9.Image = Properties.Resources.image1;
break;
case 2:
pictureBox1.Image = Properties.Resources.image2;
pictureBox8.Image = Properties.Resources.image2;
pictureBox10.Image = Properties.Resources.image2;
break;
case 3:
pictureBox1.Image = Properties.Resources.image3;
pictureBox8.Image = Properties.Resources.image3;
pictureBox10.Image = Properties.Resources.image3;
break;
case 4:
pictureBox1.Image = Properties.Resources.image4;
pictureBox8.Image = Properties.Resources.image4;
break;
case 5:
pictureBox1.Image = Properties.Resources.image5;
pictureBox8.Image = Properties.Resources.image5;
break;
case 6:
pictureBox1.Image = Properties.Resources.image6;
pictureBox8.Image = Properties.Resources.image6;
break;
case 7:
pictureBox1.Image = Properties.Resources.image7;
pictureBox8.Image = Properties.Resources.image7;
break;
case 8:
pictureBox1.Image = Properties.Resources.image8;
pictureBox8.Image = Properties.Resources.image8;
break;
}
它看起来有点恶心,我该如何改进我的代码?
您可以看看Iterator的设计模式。您可以创建一个表示单个阶段的类,该类将具有每个图片框的属性,并将这些属性的值设置为资源文件中的相关项目。
然后为每个加载阶段创建该对象的实例,将它们放在集合中,并编写迭代器来循环该集合。
有两件事我需要改进:
-
将图像存储在阵列中,这样就不必每次都重复
case X/imageX
。 -
先处理常见的事情,然后集中精力处理特殊情况。
您可以将表单中的数组声明为"伪"常量,因为它不会更改:
private readonly static Image[] myImages = new[] {
Properties.Resources.image1,
Properties.Resources.image2,
Properties.Resources.image3,
Properties.Resources.image4,
Properties.Resources.image5,
Properties.Resources.image6,
Properties.Resources.image7,
Properties.Resources.image8
}
然后在你的定时器中使用以下代码:
Image image = myImages[a-1];
pictureBox1.Image = image;
pictureBox8.Image = image;
// special cases
if (a == 1)
{
pictureBox2.Image = image;
pictureBox11.Image = image;
pictureBox9.Image = image;
}
if (a >= 1 && a <= 3)
{
pictureBox10.Image = image;
}