SQL查询:选择第1列、行数(criteria1)和行数(criteria2)

本文关键字：criteria1 criteria2 行数 查询 选择 1列 SQL | 更新日期: 2023-09-27 18:30:04

我需要一个小sql查询的帮助。考虑下表：

TicketNo | Rules          | Audit Result
---------------------------------
PR123   | some random strings | Audited
PR123   | some random strings | Not Audited
PR123   | some random strings | Audited
PR123   | some random strings | Audited
PR123   | some random strings | Not Audited
PR123   | some random strings | Not Audited
PR123   | some random strings | Audited
PR999   | some random strings | Audited
PR999   | some random strings | Audited
PR999   | some random strings | Audited
PR999   | some random strings | Audited
PR999   | some random strings | Audited
PR111   | some random strings | Not Audited
PR111   | some random strings | Not Audited
PR111   | some random strings | Not Audited
PR111   | some random strings | Not Audited

我需要以下结果：

Ticket | Count of Audited Rules | Count of NOT-Audited Rules
------------------------------------------------------------    
PR123   |   4           |   3   
PR999   |   5       |   0   
PR111   |   0       |   4

我试过了：

Select T1.TicketNo,T1.Audited_Count,T2.NonAudited_Count
FROM
(
    Select [TicketNo], COUNT([TicketNo]) AS Audited_Count
    from [Resolved Results$] where [Audit Result] = 'Audited'
    group  by TicketNo
) T1
inner JOIN
(
    Select [TicketNo], COUNT([TicketNo]) AS NonAudited_Count
    from [Resolved Results$] where [Audit Result] <> 'Audited'
    group  by TicketNo
) T2
on T1.[TicketNo] = T2.[TicketNo]

但以上命令不适用于那些具有oNLY已审核规则或oNLY未审核规则的票证，而仅适用于同时具有这两种规则的票证。

有人能帮我解决这个问题吗？

请注意：只有内部联接才能使用OleDB，因此请避免使用内部联接以外的任何联接。非常感谢

编辑：Gordon的第一个答案应该很理想，但不幸的是，Excel的OLEDB驱动程序不支持它。然而，Gordon使用iff（..）的建议奏效了。

我使用的最后一个查询是：

select [TicketNo],
       sum(iif([Audit Result] = "AUDITED", 1, 0)) as Audited,
       sum(iif([Audit Result] = "NOT AUDITED", 1, 0)) as NotAudited
from [Resolved Results$]
group by [TicketNo];

谢谢你，戈登！

SQL查询:选择第1列、行数(criteria1)和行数(criteria2)

您想要条件求和，可以通过在sum():中放入case语句来实现

select ticket,
       sum(case when AuditResult = 'Audited' then 1 else 0 end) as Audited,
       sum(case when AuditResult = 'Not Audited' then 1 else 0 end) as NotAudited
from t
group by ticket;

这是假设AuditResult是一个单独的列。如果它是SomeStrings上的最后一条注释，那么查询看起来像：

select ticket,
       sum(case when SomeStrings like '%Audited' and SomeStrings not like '%Not Audited' then 1
                else 0
           end) as Audited,
       sum(case when SomeStrings like '%Not Audited' then 1
                else 0
           end) as NotAudited
from t
group by ticket;
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