无法反序列化 xml 文件

本文关键字:文件 xml 反序列化 | 更新日期: 2023-09-27 18:30:23

我有一个如下所示的xml文件,我正在尝试反序列化。

<info>
  <result resultCode="0000"><![CDATA[操作成功]]></result>
  <songlist>
    <song>
      <id>63672</id>
      <name><![CDATA[红玫瑰]]></name>
      <singer id="1620"><![CDATA[陈奕迅]]></singer>
      <album id="22056"><![CDATA[认了吧]]></album>
      <remark><![CDATA[]]></remark>
      <uploadinguser><![CDATA[]]></uploadinguser>
      <collectinguser><![CDATA[]]></collectinguser>
      <source>
        <link id="3441591" filesize="3842715" format="mp3"><![CDATA[http://space6.j.cn/olympic/edit/672/63672-3842715.mp3]]></link>
        <link id="3435011" filesize="3843133" format="mp3"><![CDATA[http://f8.wretch.yimg.com/satyedhome/32764/1165646407.mp3]]></link>
        <link id="3434519" filesize="3842715" format="mp3"><![CDATA[http://space0.j.cn/olympic/edit/672/63672-3842715.mp3]]></link>
      </source>
    </song>
    <song>
      <id>67228</id>
      <name><![CDATA[光荣]]></name>
      <singer id="106"><![CDATA[BOBO]]></singer>
      <album id="22523"><![CDATA[光荣]]></album>
      <remark><![CDATA[]]></remark>
      <uploadinguser><![CDATA[]]></uploadinguser>
      <collectinguser><![CDATA[]]></collectinguser>
      <source>
        <link id="3437626" filesize="5106906" format="mp3"><![CDATA[http://blog.heinekenf1.net/music/gr.mp3]]></link>
        <link id="3441621" filesize="3394663" format="mp3"><![CDATA[http://space6.j.cn/olympic/edit/228/67228-3394663.mp3]]></link>
        <link id="3090938" filesize="3395499" format="mp3"><![CDATA[http://space5.j.cn/olympic/convert/228/67228-3395499.mp3]]></link>
      </source>
    </song>
    <song>...</song>
    <song>...</song>
    <song>...</song>
    <song>...</song>
    <song>...</song>
    <song>...</song>
  </songlist>
</info>

目前这是我作为模型的:

[XmlRoot("info")]
public class Response
{
    [XmlElement("result")]
    public Result Results { get; set; }
    [XmlArray("songlist")]
    [XmlArrayItem("song", typeof(Song))]
    Song[] SongList { get; set; }
}
public class Result
{
    [XmlAttribute("resultCode")]
    public int ResultCode { get; set; }
}
public class Song
{
    [XmlElement("name")]
    public string Name { get; set; }
    [XmlElement("singer")]
    public string Artist { get; set; }
    [XmlElement("album")]
    public string Album { get; set; }
    [XmlArray("source")]
    [XmlArrayItem("link", typeof(Link))]
    public Link[] Sources { get; set; }
}
public class Link
{
    [XmlAttribute("filesize")]
    public int FileSize { get; set; }
    [XmlAttribute("format")]
    public string Format { get; set; }
    [XmlText]
    public string URI { get; set; }
}

但是当我尝试使用以下代码反序列化时,它没有得到正确的解析,即我没有看到结果代码或歌曲列表(虽然没有错误)。

XmlSerializer s = new XmlSerializer(typeof(Response), new XmlRootAttribute("info"));
Response response = (Response)s.Deserialize(data.CreateReader());

有什么提示吗?

无法反序列化 xml 文件

首先确保所有属性都是公共的,因为序列化只采用公共属性。您的歌曲[]没有访问修饰符,默认为私有。

以此作为反序列化 xml 的开始。我做了一些更改来使其工作。例如,创建一个元素 SongList,使用 XmlElement 而不是 XmlArray。

[XmlRoot("info")]
public class Response
{
    [XmlElement("result")]
    public Result Result { get; set; }
    [XmlElement("songlist")]
    public SongList SongList { get; set; }
}
public class Result
{
    [XmlAttribute("resultCode")]
    public int ResultCode { get; set; }
    [XmlText]
    public string Value { get; set; }
}
public class SongList
{
    [XmlElement("song")]
    public Song[] Songs { get; set; }
}
public class Song
{
    [XmlElement("id")]
    public string Id { get; set; }
}

希望对您有所帮助!