如何遍历列表并抓取每个项目

本文关键字:抓取 项目 何遍历 遍历 列表 | 更新日期: 2023-09-27 18:31:47

如何遍历列表并抓取每个项目?

我希望输出看起来像这样:

Console.WriteLine("amount is {0}, and type is {1}", myMoney.amount, myMoney.type);

这是我的代码:

static void Main(string[] args)
{
    List<Money> myMoney = new List<Money> 
    {
        new Money{amount = 10, type = "US"},
        new Money{amount = 20, type = "US"}
    };
}
class Money
{
    public int amount { get; set; }
    public string type { get; set; }
}

如何遍历列表<T>并抓取每个项目

foreach

foreach (var money in myMoney) {
    Console.WriteLine("Amount is {0} and type is {1}", money.amount, money.type);
}

MSDN 链接

或者,因为它是一个实现索引器方法[]List<T>..,你也可以使用一个普通的for循环。 尽管它的可读性较低(IMO):

for (var i = 0; i < myMoney.Count; i++) {
    Console.WriteLine("Amount is {0} and type is {1}", myMoney[i].amount, myMoney[i].type);
}

为了完整起见,还有 LINQ/Lambda 方法:

myMoney.ForEach((theMoney) => Console.WriteLine("amount is {0}, and type is {1}", theMoney.amount, theMoney.type));

就像任何其他集合一样。 随着List<T>.ForEach方法的加入。

foreach (var item in myMoney)
    Console.WriteLine("amount is {0}, and type is {1}", item.amount, item.type);
for (int i = 0; i < myMoney.Count; i++)
    Console.WriteLine("amount is {0}, and type is {1}", myMoney[i].amount, myMoney[i].type);
myMoney.ForEach(item => Console.WriteLine("amount is {0}, and type is {1}", item.amount, item.type));
这就是

我使用更多functional way编写的方式。这是代码:

new List<Money>()
{
     new Money() { Amount = 10, Type = "US"},
     new Money() { Amount = 20, Type = "US"}
}
.ForEach(money =>
{
    Console.WriteLine($"amount is {money.Amount}, and type is {money.Type}");
});

操作代码的低级iterator

List<Money> myMoney = new List<Money>
{
    new Money{amount = 10, type = "US"},
    new Money{amount = 20, type = "US"}
};
using (var enumerator = myMoney.GetEnumerator())
{
    while (enumerator.MoveNext())
    {
        var element = enumerator.Current;
        Console.WriteLine(element.amount);
    }
}

您也可以使用 while 循环来执行此操作

   int ctr = 0;
   while (ctr <= myMoney.Count - 1)
   {
       var data = myMoney[ctr];
       Console.WriteLine($"{data.amount} - {data.type}");
       ctr++;
   }