C# 查找数组中的最小值

本文关键字：最小值 数组 查找 | 更新日期: 2023-09-27 18:31:51

    var minSalary = lstEmployeeData.Items.OfType<Employee>().Min(x => x.EmpsSalary);
    var empsWithMinSalary = lstEmployeeData.Items.OfType<Employee>().Where(x => x.EmpsSalary == minSalary);
    string names = "";
    foreach(var e in empsWithMinSalary)
    names += Environment.NewLine + e.EmployeeFirstName;
    string msg = string.Format("The following emplyoees have the lowest salary of {0} : {1}", minSalary, names);
    MessageBox.Show(msg);

上面是我查找最低工资按钮的代码，但是它说"foreach（var e in empsWithMinSalary）我收到一个错误，说 e 已经在使用中？

C# 查找数组中的最小值

查看您的代码，在我看来，您正在将文本项添加到ListBox中，因此当然要从中获得薪水并不容易。

相反，您应该将 Employee 对象传递给列表框以保留所有必要的信息;这样，您的添加方法将是：

    private void btnSave_Click(object sender, EventArgs e)
    {
        var empid = Convert.ToInt32(txtEmployeeID.Text);
        var empfirstname = Convert.ToString(txtEmployeeFirstName.Text);
        var emplastname = Convert.ToString(txtEmployeeLastName.Text);
        var empsalary = Convert.ToDouble(txtSalary.Text);
        var emp = new Employee(empid, empfirstname, emplastname, empsalary);
        lstEmployeeData.Items.Add(emp);
    }

当然，要获得所需的显示文本，您需要重新定义 Employee ToString()方法，例如：

    class Employee
    {
        // other methods...
        public override string ToString()
        {
            return this.EmployeeToString();
        }
    }

最后，当单击"显示员工有最低工资"按钮时，您应该简单地执行以下操作：

private void btnLowestSalary_Click(object sender, EventArgs e)
{
    var minSalary = lstEmployeeData.Items.OfType<Employee>().Min(x => x.Salary);
    var empWithMinSalary = lstEmployeeData.Items.OfType<Employee>()
                                          .First(x => x.Salary == minSalary);
    string msg = string.Format("{0} has the lowest salary of {1}", empWithMinSalary.EmployeeFirstName, minSalary);
    MessageBox.Show(msg);
}

编辑：

如果多个员工拥有相同的薪水，您可以执行以下操作：

private void btnLowestSalary_Click(object sender, EventArgs e)
{
    var minSalary = lstEmployeeData.Items.OfType<Employee>().Min(x => x.Salary);
    var empsWithMinSalary = lstEmployeeData.Items.OfType<Employee>()
                                           .Where(x => x.Salary == minSalary);
    foreach(var e in empsWithMinSalary)
    {
        string msg = string.Format("{0} has the lowest salary of {1}", e.EmployeeFirstName, minSalary);
        MessageBox.Show(msg);
    }
}

或更好：

private void btnLowestSalary_Click(object sender, EventArgs e)
{
    var minSalary = lstEmployeeData.Items.OfType<Employee>().Min(x => x.Salary);
    var empsWithMinSalary = lstEmployeeData.Items.OfType<Employee>()
                                           .Where(x => x.Salary == minSalary);
    string names = "";
    foreach(var e in empsWithMinSalary)
        names += Environment.NewLine + e.EmployeeFirstName;
    string msg = string.Format("The following emplyoees have the lowest salary of {0} : {1}", minSalary, names);
    MessageBox.Show(msg);
}

让我向您介绍我的朋友 Linq;

using System;
using System.Linq;
class Employee
{
    public string Name { get; set; }
        public decimal Salary { get; set; }
}
public class Test
{
    public static void Main()
    {
        Employee[] emps = new Employee[] 
        {
            new Employee { Name = "John", Salary = 9 },
            new Employee { Name = "Paul", Salary = 8 },
            new Employee { Name = "George", Salary = 6 },
            new Employee { Name = "Ringo", Salary = 6 }
        };
        decimal minSalary = emps.Min(x => x.Salary);
        foreach(var e in emps.Where(e => e.Salary == minSalary))
            Console.WriteLine("{0} {1}", e.Name, e.Salary);
    }
}

实时测试：http://ideone.com/BYjiW

这可以像这样完成：

var lowsalemp = from ee in emp where ee.empsalary == (from e in emp select e.empsalary).Min() select ee;
            foreach (var leastsalemp in lowsalemp)
            {
                Console.WriteLine(leastsalemp.empsalary);
            }
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