多个文件,同名

本文关键字:同名 文件 | 更新日期: 2023-09-27 18:32:25

我正在尝试保存一些具有相同名称的文件。我想做一些名称做这样的事情:file.extension file[1].extension file[2].extension 我已经尝试过这个 http://www.naspinski.net/post/Saving-multiple-files-of-the-same-name.aspx 但它对我不起作用。

这里有一些代码可以查看(不是整个东西,只是相关的部分),

        {
            string thepathoflife = Path.GetFullPath(file);
            //CreatetheFolder(file)
            string filetocopy = file;
            object bob = file.Clone();
            string bobby = bob.ToString();
            string location = file;
            bool b = false;
            string extension = Path.GetExtension(file);
            string thenameofdoom = Path.GetFileNameWithoutExtension(file);
            string filename = Path.GetFileName(file);
            ////bobby.Move(@"''TEST12CVG'Public'Posts'Temporaryjunk" + filename);
            // string oldlocation = filename+extension;
            if (extension == ".pst" ||
              extension == ".tec" ||
              extension == ".pas" ||
              extension == ".snc" ||
              extension == ".cst" ||
              extension == ".xml")
            {
                b = true;
            }
            if (thenameofdoom == "Plasma" ||
              thenameofdoom == "Oxygas" ||
              thenameofdoom == "plasma" ||
              thenameofdoom == "oxygas" ||
              thenameofdoom == "Oxyfuel" ||
              thenameofdoom == "oxyfuel")
            {
                b = false;
            }

            if (b == true)
            // System.IO.File.WriteAllText(newlocation, bobby);
            {
                //string rootpath = (@"''sigmatek.net'Documents'Customers'A");
                var findLevel = 6;
                var path = @thepathoflife;
                var levels = path.Split(Path.DirectorySeparatorChar);
                var second = levels.Length > findLevel ? levels[findLevel] : null;
                Directory.CreateDirectory(@"''TEST12CVG'Public'Posts'Test'" + thenameofdoom);
                string newlocation = (@"''TEST12CVG'Public'Posts'Test'" + thenameofdoom);
                string newPath = System.IO.Path.Combine(newlocation, second);
                System.IO.Directory.CreateDirectory(newPath);
                string newlocationb = Path.GetFullPath(newPath);
                    string newb = System.IO.Path.Combine(newlocationb, filename);
                        while (File.Exists(newb))
                            {
                               int number = 1;
                               bool found = false;
                               do
                               {
                                   string candidate = newb.Replace(extension, "[" + number++ + "]"+ extension);
                                   if (!File.Exists(candidate)) found = true;
                                {
                                    File.Copy(thepathoflife, candidate);
                              }
                                   // Candidate has a valid file name

                               }
                               }
                    //File.Move(@"''TEST12CVG'Public'Posts'Test'", @"''TEST12CVG'Public'Posts'Test'" + thenameofdoom + second);
                    System.Console.WriteLine("Success: " + filename + "--" + thepathoflife);
                    b = false;

多个文件,同名

这是我的

头顶。 此外,如果".extension"出现在文件名末尾以外的某处,这将中断(因此,使您的字符串处理比示例代码更智能)。 如果需要,您可以使用Path.GetExtension(path)获取扩展

if (File.Exists(fn))
{
   int number = 1;
   bool found = false;
   do
   {
       string candidate = fn.Replace(".extension", "[" + number++ + "].extension");
       if (!File.Exists(candidate)) found = true;
   }
   // Candidate has a valid file name
}
插入

"sPathAndFileName"并使用输出的"sSaveName"保存文件.
您将看到友好的递增文件名,例如:Test.txt,Text[1].txt,Test[2].txt等...

    int index = 0;
    string sSaveName = Path.GetDirectoryName(sPathAndFileName) + @"'"
                     + Path.GetFileNameWithoutExtension(sPathAndFileName)
                     + Path.GetExtension(sPathAndFileName);
    while (File.Exists(sSaveName) == true)
    {
        sSaveName = Path.GetDirectoryName(sPathAndFileName) + @"'"
                  + Path.GetFileNameWithoutExtension(sPathAndFileName)
                  + "[" + (++index).ToString() + "]"
                  + Path.GetExtension(sPathAndFileName);
    }

试试这个。简单得多。

string filename = "C:'bla.txt";
string filenameNoPath = Path.GetFileNameWithoutExtension(filename);
string temppath = Path.GetDirectoryName(filename);
string extension = Path.GetExtension(filename);
if (!File.Exists(path))
{
     File.WriteAllBytes(filename, file);
}
else
{
     do
     {
           counter++; // we're here, so lets count files with same name
           string path = temppath + "''" + filenameNoPath + "(" + counter.ToString() + ")" + extension;
     } while (File.Exists(path));
     File.WriteAllBytes(path, file);
 }

可能需要使用该Path.GetExtension(string path)才能获得文件的扩展名,然后只需剪切文件名,在其上附加迭代编号并再次扩展名。

您不能将具有相同名称和扩展名的文件放在同一个文件夹中,因此您有一个选项,例如:

  • 将它们全部放在具有有意义名称的单独目录中(即使文件具有相同的名称,内容也应该被挖掘)

  • 在前面使用日期时间戳,就像每个文件前面的 YYYYMMDD 一样(但它违反了"相同的文件名"规则)

  • 这同样可以应用于扩展

我不禁觉得这些年来我这样做了太多次。 :)

尝试以下操作:

        List<string> filesToSave = new List<string>();
        var fileName = "myfile.ext";
        var baseName = Path.GetFileNameWithoutExtension(fileName);
        var extension = Path.GetExtension(fileName);
        int counter = 1;
        foreach (var fileToSave in filesToSave)
        {
            var tempFileName = fileName;
            while (File.Exists(tempFileName))
            {
                tempFileName = string.Format("{0}{1}.{2}", baseName, counter, extension);
                counter++
            }
            File.WriteAllText(tempFileName, fileToSave);
        }

下面是一个如何帮助自己的示例:

        string[] files = { "file.txt", "file.txt", "file.txt" };
        for(int i=0;i<files.Length;i++)
        {
            string fileName = Path.GetFileNameWithoutExtension(files[i]);
            string extension = Path.GetExtension(files[i]);
            fileName = fileName + (i + 1);
            //if you would like to aqdd square brackets, you can change upper line to:
            fileName = string.Format("{0}{1}{2}{3}", fileName, "[", (i + 1), "]");
            files[i] = String.Concat(fileName, extension);
        }

如果你在FileInfo数组中有文件,你也可以这样做。