模板绑定:成员<>无法识别或无法访问
本文关键字:识别 访问 绑定 成员 | 更新日期: 2023-09-27 18:32:41
我是C#,Windows应用商店的新手,我正在努力解决一个问题。我想实现一些模板控件,它由带有进度环和文本的弹出窗口组成。
在模板类(CustomProgressRing.cs(中,我希望能够操作随附的弹出窗口及其属性。我成功地使用TextBlock,将其的文本属性设置为TempalteBinding,因此在类中我能够访问TextBlock的Text属性。我想将模板绑定应用于弹出窗口的 IsOpen 属性,但出现错误: The member "IsOpen" is not recognized or is not accessible
下面是 xaml:
<Style TargetType="local:CustomProgressRingPopup">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="local:CustomProgressRingPopup">
<Border
Background="{TemplateBinding Background}"
BorderBrush="{TemplateBinding BorderBrush}"
BorderThickness="{TemplateBinding BorderThickness}">
<Popup x:Name="ProgressRingPopup" x:Uid="LoggingInWaitingPopup" IsOpen="{TemplateBinding IsOpen}">
<Grid x:Name="gdChild" Width="Auto" Height="Auto" Background="#969696" >
<Grid.ColumnDefinitions>
<ColumnDefinition/>
<ColumnDefinition/>
</Grid.ColumnDefinitions>
<TextBlock x:Name="LoginProgressRingText" Height="Auto" Width="Auto" FontSize="20" Margin="20" VerticalAlignment="Center" Grid.Row="0" Grid.Column="1" Text="{TemplateBinding Text}"/>
</Grid>
</Popup>
</Border>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
以下是 CustomProgressRing.cs:
using System;
using System.Collections.Generic;
using System.Linq;
using Windows.UI.Xaml;
using Windows.UI.Xaml.Controls;
using Windows.UI.Xaml.Data;
using Windows.UI.Xaml.Documents;
using Windows.UI.Xaml.Input;
using Windows.UI.Xaml.Media;
using System.Diagnostics;
// The Templated Control item template is documented at http://go.microsoft.com/fwlink/?LinkId=234235
namespace QSTLibrary.WIN8.Tools
{
public sealed class CustomProgressRingPopup : Control
{
public CustomProgressRingPopup()
{
this.DefaultStyleKey = typeof(CustomProgressRingPopup);
}
public string Text
{
get { return (string)GetValue(TextProperty); }
set { SetValue(TextProperty, value); }
}
// Using a DependencyProperty as the backing store for Text. This enables animation, styling, binding, etc...
public static readonly DependencyProperty TextProperty =
DependencyProperty.Register(
"Text",
typeof(string),
typeof(CustomProgressRingPopup),
new PropertyMetadata("Void", new PropertyChangedCallback(OnTextChanged)));
private void ProgressRingPopup_Opened(object sender, object e)
{
Debug.WriteLine("Popup opened");
}
private static void OnTextChanged(DependencyObject d, DependencyPropertyChangedEventArgs e)
{
CustomProgressRingPopup instance = d as CustomProgressRingPopup;
if (instance != null)
{
string newValue = e.NewValue as string;
instance.Text = newValue;
//instance.IsOpen = true; - not working
}
}
}
}
为什么我不能将模板绑定设置为弹出窗口的 IsOpen 道具?
由于您从Control
中获得CustomProgressRingPopup
,这就是您没有获得IsOpen
财产的原因。您应该在 CustomProgressRingPopup 中定义自己的依赖属性 IsOpen 来处理它,这是一些工作。
Template binding searches the Property in the control that is being templated.