试图让球从数组组件中反弹回来?(想不出更好的词)C#.

本文关键字:更好 回来 数组 组件 | 更新日期: 2023-09-27 18:33:18

我有一个球根据需要从桨和墙壁上弹起,然后我通过抽奖添加了一块奇异的砖块。矩形工具,让球从中反弹,然后改变其颜色,但无法使其不可见以阻止任何进一步的碰撞。我正在为我的砖块使用数组,因为我可以有很多,并且可以在被击中后将它们变成真或假

我的问题是我试图让球与所说的阵列砖碰撞,但即使通过尽可能多的谷歌搜索,我一生也无法弄清楚。 这是我的代码片段,我认为"应该"适用于碰撞

 for (int i = 0; 1 < brickLive.Length; i++)
                if ((y == brickLocation[i, 0]) && (x >= brickLocation[0, i]) && (x <= (brickLocation[0, i] + 60)))
                    yChange = -yChange;

据我了解,这段代码是针对 我检查球坐标是否在砖块位置的参数中的值。 如果是,则改变方向。使用当前代码,它运行良好,直到我开始游戏(我单击插入按钮,这使弹跳按钮起作用)

这是我的完整代码

    using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace Breakout
{
    public partial class Form1 : Form
    {
        private int x, y, x2, y2;
        private int xChange, yChange;
        int bat, batX, batXX, mouseX;
        private Graphics paper;
        private Pen pen, pen2, pen3;
        private Pen brkpen;
        private Random ranNum;
        int brkLength = 60;
        int brkHeight = 20;
    int[,] brickLocation = { { 0, 100 }, { 61, 100 }, { 122, 100 } };
    bool[] brickLive = { true, true, true };

    public Form1()
    {
        InitializeComponent();
        paper = picDisplayBat.CreateGraphics();
        pen = new Pen(Color.Red);
        pen.Width = 10;
        ranNum = new Random();
        paper = picDisplayBat.CreateGraphics();
        pen = new Pen(Color.Blue);
        pen.Width = 3;
        paper = picDisplayBat.CreateGraphics();
        pen2 = new Pen(Color.Red);
        pen.Width = 3;
        picDisplayBat.MouseMove += new
        System.Windows.Forms.MouseEventHandler(picDraw_MouseMove);
        paper = picDisplayBat.CreateGraphics();
        brkpen = new Pen(Color.Black);
        brkpen.Width = 3;

        //paper = picDisplayBat.CreateGraphics();
        //pen3 = new Pen(Color.Green);
        //pen3.Width = 5;
 }

    private void picDraw_MouseMove(object sender, System.Windows.Forms.MouseEventArgs e)                         //DRAWING THE BAT TO MOVE WITH MOUSE
    {
        //paper.Clear(Color.White);
        mouseX = e.X;
    }

    private void btnInsert_Click_1(object sender, EventArgs e)
    {
        {
            btnBounce.Visible = true;
        }
    }
    private void btnBounce_Click_1(object sender, EventArgs e)
    {
        {
            timer1.Interval = 25;
            timer1.Enabled = true;
            x = ranNum.Next(1, picDisplayBat.Height);
            y = ranNum.Next(1, picDisplayBat.Width);
            xChange = ranNum.Next(1, 10); yChange = ranNum.Next(1, 10);

            for (int i = 0; i < brickLive.Length; i++)
            {
                paper.DrawRectangle(brkpen, brickLocation[i, 0], brickLocation[i, 1], brkLength, brkHeight);

            }
        }
    }
    private void timer1_Tick(object sender, EventArgs e)
    {
        {
            x = x + xChange;
            y = y + yChange;
            if (x >= picDisplayBat.Width)
                xChange = -xChange;
            if (y >= picDisplayBat.Height)
                yChange = -yChange;
            if (x <= 0)
                xChange = -xChange;
            if (y <= 0)
                yChange = -yChange;
            if ((y > picDisplayBat.Height - 20) && (x >= batX + 10) && (x <= batX + 50))
                yChange = -yChange;
            if ((y < picDisplayBat.Height - 295) && (x >= batX + 10) && (x <= batX + 50))
                yChange = -yChange;
            for (int i = 0; 1 < brickLive.Length; i++)
                if ((y == brickLocation[i, 0]) && (x >= brickLocation[0, i]) && (x <= (brickLocation[0, i] + 60)))
                    yChange = -yChange;

                paper.Clear(Color.White);
            paper.DrawRectangle(pen, mouseX + 10, picDisplayBat.Height - 20, 50, 10);          //bat 1
            paper.DrawEllipse(pen, x, y, 10, 10);                                              //ball
            paper.DrawRectangle(pen2, mouseX + 10, picDisplayBat.Height - 295, 50, 10);        //bat2
            //paper.DrawRectangle(pen3, x2, y2, 60, 10);
            bat = mouseX;
            batX = mouseX;
            batXX = mouseX;
            for (int i = 0; i < brickLive.Length; i++)
            {
                paper.DrawRectangle(brkpen, brickLocation[i, 0], brickLocation[i, 1], brkLength, brkHeight);

            }
        }
    }
    private void btnExit_Click(object sender, EventArgs e)
    {
     Environment.Exit(0);
    }
    private void btnStop_Click(object sender, EventArgs e)
    {

            timer1.Enabled = false;
            paper.Clear(Color.White);
        }
}

}

试图让球从数组组件中反弹回来?(想不出更好的词)C#.

对我来说看起来不对。

if ((y == brickLocation[i, 0]) && (x >= brickLocation[0, i]) && (x <= (brickLocation[0, i] + 60)))

在我看来,您应该始终[i, ...砖阵列位置,因此要么[i, 0]用于针对水平组件的测试,要么[i, 1]用于垂直组件。