在 ASP.net C# 中查询 Google GData Blogger API 以查找下一个博客

目前，我正在努力将"上一个博客"和"下一个博客"链接到一个 ASP.net C#应用程序，该应用程序从blogspot上托管的客户博客提供其博客。一旦我抓住一个特定的博客，我就会想立即获得它的上一个博客和下一个博客。获得以前的博客并不难。

// THIS IS MY CALL TO GET THE PREVIOUS BLOG    
FeedQuery prevQuery = new FeedQuery();
prevQuery.Uri = new Uri(String.Format("{0}", blogCred.feedUri));
    // {0} This is automatically retrieved from the database [ https://www.blogger.com/feeds/XXXXXXXXXXXXXXXXXX/posts/default/ ]
prevQuery.MaxPublication = entry.Published.AddSeconds(-1);
prevQuery.NumberToRetrieve = 1;
AtomFeed prevFeed = googleService.Query(prevQuery);
AtomEntry prevEntry = prevFeed.Entries.FirstOrDefault();
prevBlog(prevEntry);

这让我得到了我想要的结果。问题是获取下一个博客。

// THIS IS MY CALL TO GET THE NEXT BLOG   
FeedQuery nextQuery = new FeedQuery();
nextQuery.Uri = new Uri(String.Format("{0}", blogCred.feedUri)); 
    // {0} This is automatically retrieved from the database [ https://www.blogger.com/feeds/XXXXXXXXXXXXXXXXXX/posts/default/ ]
nextQuery.MinPublication = entry.Published.AddSeconds(1);
nextQuery.NumberToRetrieve = 1;
AtomFeed nextFeed = googleService.Query(nextQuery);
AtomEntry nextEntry = nextFeed.Entries.FirstOrDefault();
nextBlog(nextEntry);

我

遇到的问题是我无法让 Blogger 按降序排列这些帖子。它不断按升序对它们进行排序，并抓取已发布的最新博客，而不是下一篇文章。我不想抓取包含所有博客文章的完整 xml 文件并抓取最后一项。我想以与此 LINQ to SQL 调用类似的方式获取最后一项：

var query = from f in nextEntry
            where f.date > desiredDate
            orderby date descending
            select f;

如果有人有任何想法或我错过的任何东西 - 希望像从谷歌的回应中吐出的条目中的某个地方获取"下一篇文章"链接一样简单。

FeedQuery nextQuery = new FeedQuery();
nextQuery.Uri = new Uri(String.Format("{0}", blogCred.feedUri));
DateTime dateToFind = entry.Published.AddSeconds(1);
int numberOfDates = (int)(DateTime.Now - dateToFind).TotalDays;
nextQuery.MinPublication = dateToFind;
nextQuery.NumberToRetrieve = 1;
AtomFeed nextFeed = null;
AtomEntry nextEntry = null;
for (int i = 0; i < numberOfDates; )
{
    nextQuery.MaxPublication = dateToFind.AddDays(i);
    nextFeed = googleService.Query(nextQuery);
    if (nextFeed.TotalResults >= 1)
    {
        nextEntry = nextFeed.Entries.FirstOrDefault();
        break;
    }
    i = i + 10;
}