仅当多个孔在属性中不为零时,才会自动映射多个孔
本文关键字:零时 映射 属性 | 更新日期: 2023-09-27 18:34:14
我必须像字符串一样返回CallerAddress属性。从多个属性进行连接,除非它们不为 null。到目前为止,我已经尝试过这个,但没有工作。映射后,我的来电地址等于"Str. SomeStreetName"。我在我的数据库中查找了一下,我在其他列上有值。那么,我怎样才能使它工作呢?
Mapper.CreateMap<ClientRecordingsDao,ClientRecording>()
.ForMember(x => x.CallerAddress,
b =>
b.MapFrom(
x => x.CallerStreet != String.Empty
? "Str." + x.CallerStreet
: String.Empty +
x.CallerStreetNumber != String.Empty
? " Nr."
: String.Empty + x.CallerStreetNumber +
x.CallerBuilding != String.Empty
? " Bl."
: String.Empty + x.CallerBuilding +
x.CallerApartment != String.Empty
? " Ap."
: String.Empty + x.CallerApartment))
它+
操作符应用于错误的位置。将每个比较包装在()
:
Mapper.CreateMap<ClientRecordingsDao,ClientRecording>()
.ForMember(x => x.CallerAddress, b => b.MapFrom(
x => (x.CallerStreet != String.Empty ? "Str." + x.CallerStreet : String.Empty) +
(x.CallerStreetNumber != String.Empty ? " Nr." + x.CallerStreetNumber : String.Empty) +
(x.CallerBuilding != String.Empty ? " Bl." + x.CallerBuilding : String.Empty) +
(x.CallerApartment != String.Empty ? " Ap." + x.CallerApartment : String.Empty)));
您的代码映射到以下内容:
Mapper.CreateMap<ClientRecordingsDao,ClientRecording>()
.ForMember(x => x.CallerAddress, b => b.MapFrom(
x => x.CallerStreet != String.Empty ? "Str." + x.CallerStreet :
(String.Empty + x.CallerStreetNumber != String.Empty ? " Nr." + x.CallerStreetNumber :
(String.Empty + x.CallerBuilding != String.Empty ? " Bl." + x.CallerBuilding :
(String.Empty + x.CallerApartment != String.Empty ? " Ap." + x.CallerApartment : String.Empty)))));