如何在按钮内显示Microsoft Ajax 的进度栏
本文关键字:Ajax Microsoft 显示 按钮 | 更新日期: 2023-09-27 18:35:50
我想显示 microsoft ajax 的进度栏,当用户单击该按钮时,该按钮内有一个图像。 但我不知道该怎么做?我知道如何在按钮内显示 progressbar.my 问题!
<asp:UpdateProgress ID="UpdateProgress1" runat="server" AssociatedUpdatePanelID="up">
<ProgressTemplate>
<div class="PlaeseWaite">
</div>
</ProgressTemplate>
</asp:UpdateProgress>
你的 aspx 代码
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
<style type="text/css">
.modalPopup
{
background-color: #696969;
filter: alpha(opacity=40);
opacity: 0.7;
xindex:-1;
}
</style>
</head>
<body>
<form id="form1" runat="server">
<asp:ScriptManager ID="ScriptManager1" runat="server"/>
<script type="text/javascript">
var prm = Sys.WebForms.PageRequestManager.getInstance();
//Raised before processing of an asynchronous postback starts and the postback request is sent to the server.
prm.add_beginRequest(BeginRequestHandler);
// Raised after an asynchronous postback is finished and control has been returned to the browser.
prm.add_endRequest(EndRequestHandler);
function BeginRequestHandler(sender, args) {
//Shows the modal popup - the update progress
var popup = $find('<%= modalPopup.ClientID %>');
if (popup != null) {
popup.show();
}
}
function EndRequestHandler(sender, args) {
//Hide the modal popup - the update progress
var popup = $find('<%= modalPopup.ClientID %>');
if (popup != null) {
popup.hide();
}
}
</script>
<div>
<asp:UpdateProgress ID="UpdateProgress" runat="server">
<ProgressTemplate>
<asp:Image ID="Image1" ImageUrl="waiting.gif" AlternateText="Processing" runat="server" />
</ProgressTemplate>
</asp:UpdateProgress>
<ajaxToolkit:ModalPopupExtender ID="modalPopup" runat="server" TargetControlID="UpdateProgress"
PopupControlID="UpdateProgress" BackgroundCssClass="modalPopup" />
<asp:UpdatePanel ID="pnlData" runat="server" UpdateMode="Conditional">
<ContentTemplate>
<asp:Button ID="btnSubmit" runat="server" Text="Submit" onclick="btnSubmit_Click"/>
</ContentTemplate>
</asp:UpdatePanel>
</div>
</form>
</body>
</html>
和代码隐藏
protected void btnSubmit_Click(object sender, EventArgs e)
{
System.Threading.Thread.Sleep(2000);
}
这是解决方案