从基于条件的列表创建 XML 文件
本文关键字：列表 创建 XML 文件 条件 于条件 | 更新日期: 2023-09-27 18:36:16
我一直试图理解它几个小时，但没有运气。我有一个基于类的列表：
public class xmldata //Class to receive items list
{
public string xml_filename { get; set; }
public string colorname { get; set; }
public string colorvalues { get; set; }
}
然后我做了一个单独的类来保存列表：
public class xmldatalist
{
public List<xmldata> FullList = new List<xmldata>();
}
此列表（FullList）的每个位置都包含来自xmldata的三个元素 - 我想关注的特定元素是xml_filename。
我的问题是：我怎样才能有一个foreach循环来迭代这个列表，并为每个xml_filename值生成一个XML文件。
即：从位置 0 到 5，xml_filename是 file1.bla从位置 6 到 9，xml_filename是 file2.bla
我想要一个将迭代低谷位置 0 到 5 的 foreach，检查xml_filename是否为 file1.bla 并写入位置 0 到 5 的属性。
像这样：
检查xml_filename创建文件写入属性如果下一个位置xml_filename相同继续写在这个文件如果下一个位置xml_file不同，则写入新文件
现在我正在尝试使用 Linq，方法是这样做：
foreach (var ListXmlFileName in XMLList.FullList.Where(x => x.xml_filename == XmlFilename))
{
}
但我有点不知道如何进行。我尝试的另一种方法是：
foreach (xmldata XmlStuff in XmlItems.ItemsList)
{
}
没有成功也。编写 XML 的代码是：
public void writexml(xmldatalist XmlItems, variables GlobalVars)
{
XmlWriterSettings settings = new XmlWriterSettings
{
Indent = true,
IndentChars = "'t",
NewLineChars = Environment.NewLine,
NewLineHandling = NewLineHandling.Replace,
Encoding = new UTF8Encoding(false)
};
int pos = 0;
foreach (xmldata XmlStuff in XmlItems.ItemsList)
{
string DesktopFolder = Environment.GetFolderPath(Environment.SpecialFolder.DesktopDirectory);
string XmlFilename = "dadada";
string FileExtension = ".xml";
string PathString = Path.Combine(DesktopFolder, "XML");
System.IO.Directory.CreateDirectory(PathString);
string FullPath = Path.Combine(PathString, XmlFilename + FileExtension);
XmlWriter XmlWriting = XmlWriter.Create(FullPath, settings);
XmlWriting.WriteStartDocument();
XmlWriting.WriteStartElement("JMF");
XmlWriting.WriteAttributeString("SenderID", "InkZone-Controller");
XmlWriting.WriteAttributeString("Version", "1.2");
//XmlWriting.WriteAttributeString("xmlns","",null, "http://www.CIP4.org/JDFSchema_1_1");
XmlWriting.WriteStartElement("Command");
XmlWriting.WriteAttributeString("ID", "cmd.00695");
XmlWriting.WriteAttributeString("Type", "Resource");
XmlWriting.WriteStartElement("ResourceCMDParams");
XmlWriting.WriteAttributeString("ResourceName", "InkZoneProfile");
XmlWriting.WriteAttributeString("JobID", "K_41");
XmlWriting.WriteStartElement("InkZoneProfile");
XmlWriting.WriteAttributeString("ID", "r0013");
XmlWriting.WriteAttributeString("Class", "Parameter");
XmlWriting.WriteAttributeString("Locked", "false");
XmlWriting.WriteAttributeString("Status", "Available");
XmlWriting.WriteAttributeString("PartIDKeys", "SignatureName SheetName Side Separation");
XmlWriting.WriteAttributeString("DescriptiveName", "Schieberwerte von DI");
XmlWriting.WriteAttributeString("ZoneWidth", "32");
XmlWriting.WriteStartElement("InkZoneProfile");
XmlWriting.WriteAttributeString("SignatureName", "SIG1");
XmlWriting.WriteStartElement("InkZoneProfile");
XmlWriting.WriteAttributeString("Locked", "False");
XmlWriting.WriteAttributeString("SheetName", "S1");
XmlWriting.WriteStartElement("InkZoneProfile");
XmlWriting.WriteAttributeString("Side", "Front");
我也试过这个，但没有按预期工作（while循环）
while(XmlStuff.xml_filename == XmlItems.ItemsList[pos].xml_filename)
{
XmlWriting.WriteStartElement("InkZoneProfile");
XmlWriting.WriteAttributeString("Separation", XmlItems.ItemsList[pos].colorname);
XmlWriting.WriteAttributeString("ZoneSettingsX", XmlItems.ItemsList[pos].colorvalues);
XmlWriting.WriteEndElement();
pos++;
}
XmlWriting.WriteEndDocument();
XmlWriting.Close();
}
}
任何帮助将不胜感激。多谢。
**
编辑：XML 示例
**.
<?xml version="1.0" encoding="utf-8"?>
<JMF SenderID="InkZone-Controller" Version="1.2" xmlns="http://www.CIP4.org/JDFSchema_1_1">
<Command ID="cmd.00695" Type="Resource">
<ResourceCmdParams ResourceName="InkZoneProfile" JobID="K_41">
<InkZoneProfile ID="r0013" Class="Parameter" Locked="false" Status="Available" PartIDKeys="SignatureName SheetName Side Separation" DescriptiveName="Schieberwerte von DI" ZoneWidth="32">
<InkZoneProfile SignatureName="SIG1">
<InkZoneProfile Locked="false" SheetName="S1">
<InkZoneProfile Side="Front">
<InkZoneProfile Separation="designer P&G 1901" ZoneSettingsX="0.391 0.36 0.097 0.058 0 0 0 0 0 0 0 0 0.178 0.394 0.201 0.088"/>
<InkZoneProfile Separation="designer P&G 0323" ZoneSettingsX="0.011 0.028 0.02 0.021 0.079 0.071 0.046 0.059 0.043 0.062 0.044 0.094 0.024 0.037 0.012 0.023"/>
<InkZoneProfile Separation="designer P&G 0068" ZoneSettingsX="0 0.04 0.03 0.016 0.08 0.005 0.041 0.036 0.034 0.044 0.028 0.072 0.001 0.005 0.063 0.008"/>
<InkZoneProfile Separation="designer P&G 0056" ZoneSettingsX="0 0.064 0.053 0.032 0.137 0.022 0.164 0.097 0.153 0.11 0.052 0.127 0.01 0.007 0.108 0.008"/>
<InkZoneProfile Separation="designer P&G 0306" ZoneSettingsX="0 0 0 0.19 0.187 0.259 0.224 0.178 0.24 0.185 0.249 0.188 0.173 0 0 0.004"/>
<InkZoneProfile Separation="designer P&G 0016" ZoneSettingsX="0.069 0.1 0.21 0.049 0.07 0.027 0.138 0.265 0.134 0.242 0.056 0.066 0.039 0.09 0.17 0.13"/>
<InkZoneProfile Separation="designer P&G 0057" ZoneSettingsX="0 0 0 0 0.023 0.001 0.012 0.012 0.008 0.016 0.003 0.021 0.001 0 0 0.004"/>
<InkZoneProfile Separation="Keyline" ZoneSettingsX="0.013 0.006 0.006 0.038 0.007 0.033 0.012 0.026 0.018 0.02 0.016 0.007 0.034 0.006 0.006 0.022"/>
</InkZoneProfile>
</InkZoneProfile>
</InkZoneProfile>
</InkZoneProfile>
这会更准确：
<InkZoneProfile Separation="Cyan" ZoneSettingsX="0.391 0.36 0.097 0.058 0 0 0 0 0 0 0 0 0.178 0.394 0.201 0.088"/>
假设它属于文件 1。文件1将有五个SomeColor 和 SomeValues 位于列表的每个位置。
这是你想要的吗：
[Serializable]
[XmlType("InkZoneProfile")]
public class xmldata //Class to receive items list
{
[XmlIgnore]
public string xml_filename { get; set; }
[XmlAttribute("Separation")]
public string colorname { get; set; }
[XmlAttribute("ZoneSettingsX")]
public string colorvalues { get; set; }
}
FullList.Add(new xmldata { xml_filename = @"D:'File_One", colorname = "Red", colorvalues = "#FF0000" });
FullList.Add(new xmldata { xml_filename = @"D:'File_One", colorname = "Blue", colorvalues = "#0000FF" });
FullList.Add(new xmldata { xml_filename = @"D:'File_Two", colorname = "Black", colorvalues = "#000000" });
FullList.Add(new xmldata { xml_filename = @"D:'File_Two", colorname = "White", colorvalues = "#FFFFFF" });
Dictionary<string, List<xmldata>> xmlFiles = new Dictionary<string, List<xmldata>>();
foreach (var item in FullList)
{
if (!xmlFiles.ContainsKey(item.xml_filename)) xmlFiles[item.xml_filename] = new List<xmldata>();
xmlFiles[item.xml_filename].Add(item);
}
foreach (var i in xmlFiles)
{
string yourXMLFileName = i.Key;
List<xmldata> xmlDataOfThisFile = i.Value;
Console.WriteLine(yourXMLFileName);
try
{
using (FileStream fs = new FileStream(yourXMLFileName, FileMode.Create, FileAccess.Write, FileShare.None))
{
XmlSerializer serializer = new XmlSerializer(typeof(List<xmldata>));
serializer.Serialize(fs, FullList);
}
}
catch(Exception ex)
{
Console.WriteLine(ex.Message);
Console.WriteLine(ex.InnerException);
}
}
这将创建此 XML：
<?xml version="1.0"?>
<ArrayOfInkZoneProfile xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<InkZoneProfile Separation="Red" ZoneSettingsX="#FF0000" />
<InkZoneProfile Separation="Blue" ZoneSettingsX="#0000FF" />
<InkZoneProfile Separation="Black" ZoneSettingsX="#000000" />
<InkZoneProfile Separation="White" ZoneSettingsX="#FFFFFF" />
</ArrayOfInkZoneProfile>
编辑
根据您的评论，您还有其他问题。当标题问题的问题现在得到解决时，您应该用其他问题提出新问题。不要在这里合并。