onSuccess和onFailure;不要被解雇
本文关键字:onFailure onSuccess | 更新日期: 2023-09-27 17:59:01
我在PageMethod调用中使用了onSuccess和onFailure。然而,它们都不会被调用,WebMethod也不会被解雇。
alert("1");
PageMethods.LoginUser(onSuccess, onFailure, email, pass);
alert("2");
function onSuccess(val)
{
}
function onFailure()
{
}
[WebMethod(EnableSession = true)]
public static int LoginUser(string email, string pass)
{
//Doesn't get fired
}
当我删除它们并只将值发送到WebMethod时,它就起作用了:
PageMethods.LoginUser(email, pass);
//This fires the Web Method
我也在ScriptManager中启用了PageMethods。我做错了什么?
您的PageMethod看起来像这个
PageMethods.LoginUser(onSuccess, onFailure, email, pass);
当你调用它时,它看起来像这个
PageMethods.LoginUser(email, pass);
参数的顺序应该与方法的顺序相同。
PageMethods.LoginUser(email, pass, onSuccess, onFailure);