当某些条件发生时，如何在while循环中保持变量的随机化值恒定

本文关键字：循环 变量 随机化 while 条件 | 更新日期: 2023-09-27 18:00:47

我试着做一个基本的数字猜谜游戏。然而，我找不到保持随机数不变的方法，以便为用户提供增加或减少猜测的线索。这对你来说很容易，但我需要你有价值和有用的观点。附言：是的，我是个初学者。

 while (true)
 {
     Random rd = new Random();
     Console.WriteLine("guess a number 0-10");
     guess = int.Parse(Console.ReadLine());
     comp = rd.Next(10);
     if (guess == comp)
     {
         Console.WriteLine("congratz!! u won!!");
         Console.WriteLine("press any key to exit");
         break;
     }
     // Those are the conditions for directing user.I couldn't   implement it.
     //else if (guess > comp)
     //    Console.WriteLine("your guess is greater than my number, yow!");
     //else if (guess < comp)
     //    Console.WriteLine("your guess is lower than my number, yow!");

     Console.WriteLine("loser!!" + "My number was:" + comp);
 }
 Console.ReadLine();

当某些条件发生时，如何在while循环中保持变量的随机化值恒定

你可能想这样做：

Random rd = new Random();
int comp = rd.Next(10); // Store you random number before the loop
int guess = 0;
int trylimit = 3;
int round = 0;
while (round < trylimit)
    {
        Console.WriteLine("guess a number 0-10");
        guess = int.Parse(Console.ReadLine());
        if (guess == comp)
            {
                Console.WriteLine("congratz!! u won!!");
                Console.WriteLine("press any key to exit");
                break;
            }
        else if (guess > comp)
            Console.WriteLine("your guess is greater than my number, yow!");
        else if (guess < comp)
            Console.WriteLine("your guess is lower than my number, yow!");
            round++;
    }
Console.WriteLine("loser!!" + "My number was:" + comp + "'n");
Console.ReadLine();

正如Tim Schmelter在评论中所说，您需要在while loop之前声明并初始化random，否则每次进入循环时都可能发生更改。

正如我在评论中所说，在循环之前声明并初始化Random实例，否则如果循环执行得很快，您将始终生成相同的数字。这在这里可能不是问题，因为Console.ReadLine()停止执行，但无论如何都要知道这一点。

如果您想要一个介于0和10之间的数字，则必须使用rd.Next(11)，因为最大值是独占的。如果用户输入了无效整数，请使用int.TryParse来防止出现异常。

然后，您可以使用for-loop只询问用户n次并提供线索。

int numTries = 3;
Random rd = new Random();
while (true)
{
    Console.WriteLine("guess a number 0-10");
    int number = rd.Next(11); // 0-10
    for (int currentTry = 1; currentTry <= numTries; currentTry++)
    {
        int guess;
        if (!int.TryParse(Console.ReadLine().Trim(), out guess))
        {
            Console.WriteLine("Please enter a valid integer between 0 and 10!");
            continue;  // next try
        }
        if (guess == number)
        {
            Console.WriteLine("congratz!! u won!!");
            break;  // breaks for-loop
        }
        else if(currentTry == numTries)  // last try
            Console.WriteLine("loser!!" + "My number was: " + number);
        else if (guess < number)
            Console.WriteLine("your guess is lower than my number, yow!");
        else if (guess > number)
            Console.WriteLine("your guess is greater than my number, yow!");
    }
}

在宣布用户为失败者之前，您可以询问用户n次。当然，我没有检查正确的用户输入；小心非数字用户输入！

Random rnd = new Random();
int comp = rnd.Next(10);
int guess;
int numberofGuesses = 3;
int counter = 0;
        Console.WriteLine("guess a number 0-10");
        do
        {
            guess = int.Parse(Console.ReadLine());
            if (guess == comp)
            {
                Console.WriteLine("congratz!! u won!!");
                Console.WriteLine("press any key to exit");
                Console.ReadKey();
                return;
            }
            else
            {
                if (guess > comp)
                {
                    Console.WriteLine("your guess is greater than my number, yow!");
                }
                else
                {
                    Console.WriteLine("your guess is lower than my number, yow!");
                }
                if(counter!=numberofGuesses - 1)
                    Console.WriteLine("Guess again!");
                counter++;
            }
        } while (counter < numberofGuesses);

        Console.WriteLine("loser!!" + "My number was:" + comp);
        Console.ReadKey();
        return;
    }
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