如何将此JSON结果解析为对象

本文关键字：对象 结果 JSON | 更新日期: 2023-09-27 18:00:52

我需要将这个JSON字符串解析为"WeatherJson"类型的对象。然而，我不知道如何解析字符串中的数组，例如"weather"：[{"id":802,"main":"Clouds","description":"scattered clouds","icon":"03d"}]。实体类会是什么样子？

JSON字符串：

{
  "coord": {"lon":79.85,"lat":6.93},
  "sys": {
    "type": 1, 
    "id": 7864, 
    "message": 0.0145,
    "country": "LK",
    "sunrise": 1435883361,
    "sunset": 1435928421
  },
  "weather": [
     {"id":802, "main":"Clouds", "description":"scattered clouds", "icon":"03d"}
  ],
  "base": "stations",
  "main": {
    "temp": 302.15,
    "pressure": 1013,
    "humidity": 79,
    "temp_min": 302.15,
    "temp_max": 302.15
  },
  "visibility":10000,
  "wind": { "speed": 4.1, "deg": 220 },
  "clouds": { "all": 40 },
  "dt": 1435893000,
  "id":1248991,
  "name":"Colombo",
  "cod":200
}

编辑

我需要从代码中检索以下值：

WeatherJson w = new WeatherJson();
Console.WriteLine(w.weather.description);
//that above line was retrieved and stored from the JSONArray named 'weather' in the main json response

如何将此JSON结果解析为对象

您只需使JSON中的数组与POCO中的列表或数组类型匹配即可。下面是一个使用您提供的JSON的简短但完整的示例：

using System;
using System.Collections.Generic;
using System.IO;
using Newtonsoft.Json;
class Test
{ 
    static void Main(string[] args) 
    {
        var json = File.ReadAllText("weather.json");
        var root = JsonConvert.DeserializeObject<Root>(json);
        Console.WriteLine(root.Weather[0].Description);
    }
}
public class Root
{
    // Just a few of the properties
    public Coord Coord { get; set; }
    public List<Weather> Weather { get; set; }
    public int Visibility { get; set; }
    public string Name { get; set; }
}
public class Weather
{
    public int Id { get; set; }
    public string Description { get; set; }
}
public class Coord
{
    public double Lon { get; set; }
    public double Lat { get; set; }
}

这样尝试：

void Main()
{
    var json = System.IO.File.ReadAllText(@"d:'test.json");
    var objects = JArray.Parse(json); // parse as array  
    foreach(JObject root in objects)
    {
        foreach(KeyValuePair<String, JToken> app in root)
        {
            var appName = app.Key;
            var description = (String)app.Value["Description"];
            var value = (String)app.Value["Value"];
            Console.WriteLine(appName);
            Console.WriteLine(description);
            Console.WriteLine(value);
            Console.WriteLine("'n");
        }
    }
}

试试这个，希望它能帮助你。。。。

      var dataObj=JSON.parse {"coord":{"lon":79.85,"lat":6.93},"sys":
      {"type":1,"id":7864,"message":0.0145,"country":"LK",
 "sunrise":1435883361,
"sun        set":1435928421},"weather":     [{"id":802,"main":"Clouds",
    "description":"scattered    clouds","icon":"03d"}],
  "base":"stations","main":{"temp":302.15,"pressure":1013,
"humidity":79,"temp_min":302.15,
 "temp_max":302.15},"visibility":10000,"wind":{"speed":4.1,"deg":220},
 "clouds":{"all":40},"dt":1435893000,"id":1248991,
  "name":"Colombo","cod":200}
to read this .
i m reading one single string so u can able to know.
var windData=dataObj.wind.speed;
 it will read value 4.1 from your string like this..
If u want to read array of string then..
var weatherObj=dataObj.weather[0].description;
so it will read  description value from array.like this u can read.

尝试双重迭代，

for (key in parent) {
     for(key1 in parent[key]){
     //
     }
}
JObject为此定义了方法Parse： 
JObject json = JObject.Parse(JsonString);

您可能需要参考Json.NET文档。

如果你有对象的集合，那么你可以使用JArray

JArray jarr = JArray.Parse(JsonString);

有关文档，请参阅此处。

将JArry转换为List只需输入以下方法。它会归还你需要的东西。

Jarray.ToObject<List<SelectableEnumItem>>()

您可以使用JavaScriptSerializer类将JSON解析为Object。

请参阅此StackOverflow线程

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