动态反映WPF应用程序中的更改
本文关键字:应用程序 WPF 动态 | 更新日期: 2023-09-27 18:01:09
我正在运行一个WPF应用程序,并想做这样的事情:
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
TextBox textBox = new TextBox();
mainGrid.Children.Add(textBox);
textBox.Text = "one";
Thread.Sleep(1000);
textBox.Text = "two";
Thread.Sleep(1000);
textBox.Text = "three";
Thread.Sleep(1000);
textBox.Text = "four";
}
}
在所有这些处理完成之前,显示器不会加载,因此我有一个空白的、无响应的应用程序,直到3秒钟,在运行上述代码后,还有一个带有单词"四"的文本框。
我看了一眼BackgroundWorker课程,并尝试了这个:
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
// Set up background worker object & hook up handlers
BackgroundWorker backgroundWorker;
backgroundWorker = new BackgroundWorker();
backgroundWorker.DoWork += new DoWorkEventHandler(bgWorker_DoWork);
backgroundWorker.RunWorkerCompleted += new RunWorkerCompletedEventHandler(bgWorker_RunWorkerCompleted);
backgroundWorker.RunWorkerAsync();
}
private void bgWorker_DoWork(object sender, DoWorkEventArgs e)
{
Application.Current.Dispatcher.Invoke(DispatcherPriority.Normal, new Action(() =>
{
TextBox textBox = new TextBox();
mainGrid.Children.Add(textBox);
textBox.Text = "one";
Thread.Sleep(1000);
textBox.Text = "two";
Thread.Sleep(1000);
textBox.Text = "three";
Thread.Sleep(1000);
textBox.Text = "four";
}));
}
private void bgWorker_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
Debug.WriteLine("done");
}
还是一样的行为。我想在后台/不同的线程中运行一些任务,这些任务将在执行过程中对UI元素进行更改,我希望这些更改立即反映在显示中。
考虑使用async
和await
:
private async void Window_Loaded(object sender, RoutedEventArgs e)
{
TextBox textBox = new TextBox();
mainGrid.Children.Add(textBox);
textBox.Text = "one";
await Task.Delay(1000);
textBox.Text = "two";
await Task.Delay(1000);
textBox.Text = "three";
await Task.Delay(1000);
textBox.Text = "four";
}
这是关于这个主题的一个相当不错的教程。
我同意前面的海报,但如果你想使用后台工作者,请考虑看一下本教程:http://www.wpf-tutorial.com/misc/multi-threading-with-the-backgroundworker/
[…]被称为DoWork,一般规则是您不能从该事件中触摸UI中的任何内容。相反,您调用ReportProgress((方法,该方法进而引发ProgressChanged事件,您可以从中更新UI。完成后,将结果分配给工作者,然后引发RunWorkerCompleted事件。
基本上,UI需要在一个线程上运行。否则你就失去了分数。
async await可能是最好的答案,但在这种情况下也可以使用计时器。
System.Timers.Timer t;
private void Window_Loaded(object sender, RoutedEventArgs e)
{
t = new System.Timers.Timer();
t.Elapsed += t_Elapsed;
t.Interval = 1000;
t.Start();
}
int tickCount = 0;
void t_Elapsed(object sender, System.Timers.ElapsedEventArgs e)
{
tickCount++;
switch (tickCount)
{
case 1: textBox.Text = "one"; break;
case 2: textBox.Text = "two"; break;
case 3: textBox.Text = "three"; break;
case 4: textBox.Text = "four"; break;
case 5: t.Stop(); break;
}
}