生成相同的随机数

本文关键字：随机数 | 更新日期: 2023-09-27 18:01:30

    private int left;
    private int middle;
    private int right;
    public Form1()
    {
        InitializeComponent();
    }
    private void Form1_Load(object sender, EventArgs e)
    {
        Random r = new Random();
        left = r.Next(1, 4);
        middle = r.Next(1, 4);
        right = r.Next(1, 4);
        while (left == middle)
        {
            left = r.Next(1, 4);
            middle = r.Next(1, 4);                
        }
        while (left == right)
        {
            left = r.Next(1, 4);
            right = r.Next(1, 4);
        }
        while (middle == left)
        {
            middle = r.Next(1, 4);
            left = r.Next(1, 4);
        }
        while (middle == right)
        {
            middle = r.Next(1, 4);
            right = r.Next(1, 4);
        }
        while (right == left)
        {
            right = r.Next(1, 4);
            left = r.Next(1, 4);
        }
        while(right == middle)
        {
            right = r.Next(1, 4);
            middle = r.Next(1, 4);
        }
}

到目前为止，这是我所拥有的，但我不希望这三个变量具有相同的数字，我认为while循环会解决这个问题，但它没有。我还是c#新手，有人有什么建议吗?

生成相同的随机数

这样做可能更容易:

var r = new Random();
var numbers = new List<int> { 1, 2, 3 }.OrderBy(n => r.Next()).ToList();
left = numbers[0];
middle = numbers[1];
right = numbers[2];

这将打乱你想要的数字，然后你可以将它们分配给你的三个变量。它还保证不会永远循环，因为您知道您的值已经是唯一的。

你想让数字1、2和3以某种随机顺序排列吗?一种解决方案是创建一个列表，并以随机顺序提取项目。下面是一个简单的例子:

Random r = new Random();
var numbers = new List<int> { 1, 2, 3 };
left = TakeRandom(numbers, r);
middle = TakeRandom(numbers, r);
right = numbers[0];
...
private static int TakeRandom(List<int> list, Random r)
{
    var index = r.Next(0, list.Count);
    var result = list[index];
    list.RemoveAt(index);
    return result;
}

当然，可能有更优雅的方式来写它(我想到了扩展方法)，但我认为这已经传达了重点。

使用这个循环来确保这三个都是不同的

while (left == middle || middle == right || right == left) {
    left = r.Next(1,4);
    middle = r.Next(1,4);
    right = r.Next(1,4);
}

你为什么不试试呢?

Random r = new Random();
left = r.Next(1,4), middle = r.Next(1,4), right = r.Next(1,4);
while ( left == middle || middle == right || left == right){
   left = r.Next(1,4); middle = r.Next(1,4); right = r.Next(1,4);
}

——或

Random r = new Random();
left = r.Next(1,4); middle = r.Next(1,4); right = r.Next(1,4);
while ( left == middle ){
   middle = r.Next(1,4);
}
while (left == right || middle == right){
   right = r.Next(1,4);
}

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