c# OpenFileDialog不打开文件
本文关键字:文件 OpenFileDialog | 更新日期: 2023-09-27 18:01:42
我试图使用openFileDialog打开位图图像并将其放在我的表单上。我的表单构造器…
public Form1()
{
InitializeComponent();
drawing = new Bitmap(drawingPanel.Width, drawingPanel.Height, drawingPanel.CreateGraphics());
Graphics.FromImage(drawing).Clear(Color.White);
// set default value for line thickness
tbThickness.Text = "5";
}
…打开一个带有空白屏幕的新表单,我可以使用鼠标和各种颜色选择器按钮在其上绘图。然后用以下方法保存文件:
private void btnSave_Click(object sender, EventArgs e)
{
// save drawing
if (file == null) // file is a FileInfo object that I want to use
// to check to see if the file already exists
// I haven't worked that out yet
{
drawing.Save("test.bmp");
//SaveBitmap saveForm = new SaveBitmap();
//saveForm.Show();
}
else
{
drawing.Save(fi.FullName);
}
}
图像以bmp文件的形式保存到调试文件夹中。然后我使用OpenFileDialog打开文件:
private void btnOpen_Click(object sender, EventArgs e)
{
FileStream myStream;
OpenFileDialog openFile = new OpenFileDialog();
openFile.Filter = "bmp files (*.bmp)|*.bmp";
if (openFile.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = (FileStream)openFile.OpenFile()) != null)
{
using (myStream)
{
PictureBox picBox = new PictureBox();
picBox.Location = drawingPanel.Location;
picBox.Size = drawingPanel.Size;
picBox.Image = new Bitmap(openFile.FileName);
this.Controls.Add(picBox);
}
}
}
catch (Exception ex)
{
}
}
}
会出现OpenFileDialog对话框。当我选择文件test.bmp时,屏幕消失,然后重新出现,当我再次选择它时,OpenFileDialog窗口消失,我回到了没有图像的表单。我希望你能给点建议。没有编译或运行时错误。
为什么要两次呼叫ShowDialog()
?
只调用ShowDialog
一次,所以它不会像您指示的那样打开两次。
OpenFileDialog openFileDialog1 = new OpenFileDialog();
openFileDialog1.Filter = "bmp files (*.bmp)|*.bmp";
if(openFileDialog1.ShowDialog() == DialogResult.OK)
{
try
{
if ((myStream = openFileDialog1.OpenFile()) != null)
{
using (myStream)
{
// Insert code to read the stream here.
PictureBox picBox = new PictureBox();
picBox.Location = drawingPanel.Location;
picBox.Size = drawingPanel.Size;
picBox.Image = new Bitmap (myStream);
this.Controls.Add(picBox);
}
}
}
catch (Exception ex)
{
MessageBox.Show("Error: Could not read file from disk. Original error: " + ex.Message);
}
}
你打开一个对话框面板,然后当它关闭时,你检查一下结果是否OK;然后在using
块中打开另一个新对话框;然后将其图像结果分配给PictureBox
,然后在using
块处置时将其全部丢弃。
您调用ShowDialogue
两次,这可能是您的问题的根源。只需使用以下代码,从方法中删除其他所有内容。您使用using
也是不正确的。它确实清理了谁在处理结果。你需要重构或删除using语句。
private void btnOpen_Click(object sender, EventArgs e)
{
OpenFileDialog dlg = new OpenFileDialog()
{
dlg.Title = "Open Image";
dlg.Filter = "bmp files (*.bmp)|*.bmp";
if (dlg.ShowDialog() == DialogResult.OK)
{
PictureBox picBox = new PictureBox();
picBox.Location = drawingPanel.Location;
picBox.Size = drawingPanel.Size;
picBox.Image = new Bitmap (dlg.FileName);
this.Controls.Add(picBox);
}
}
}
上面的代码可以工作,但没有清理或错误处理。