循环遍历configrationsection,使用c#读取它的'
本文关键字:读取 遍历 configrationsection 使用 循环 | 更新日期: 2023-09-27 17:50:14
我有一个配置文件,类似:
<logonurls>
<othersettings>
<setting name="DefaultEnv" serializeAs="String">
<value>DEV</value>
</setting>
</othersettings>
<urls>
<setting name="DEV" serializeAs="String">
<value>http://login.dev.server.com/Logon.asmx</value>
</setting>
<setting name="IDE" serializeAs="String">
<value>http://login.ide.server.com/Logon.asmx</value>
</setting>
</urls>
<credentials>
<setting name="LoginUserId" serializeAs="String">
<value>abc</value>
</setting>
<setting name="LoginPassword" serializeAs="String">
<value>123</value>
</setting>
</credentials>
</logonurls>
如何读取配置以获得传递的keyname的值?下面是我写的方法:
private static string GetKeyValue(string keyname)
{
string rtnvalue = String.Empty;
try
{
ConfigurationSectionGroup sectionGroup = config.GetSectionGroup("logonurls");
foreach (ConfigurationSection section in sectionGroup.Sections)
{
//I want to loop through all the settings element of the section
}
}
catch (Exception e)
{
}
return rtnvalue;
}
config是配置变量,它包含配置文件中的数据。
将配置文件加载到XmlDocument中,通过名称(要读取的设置值)获取XmlElement,并尝试以下代码:
System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
doc.LoadXml(xmlfilename);
XmlElement elem = doc.GetElementByName("keyname");
var allDescendants = myElement.DescendantsAndSelf();
var allDescendantsWithAttributes = allDescendants.SelectMany(elem =>
new[] { elem }.Concat(elem.Attributes().Cast<XContainer>()));
foreach (XContainer elementOrAttribute in allDescendantsWithAttributes)
{
// ...
}
如何编写一个LINQ to XML查询来遍历所有子元素&子元素的所有属性?
将其转换为适当的XML并在节点内搜索:
private static string GetKeyValue(string keyname)
{
string rtnValue = String.Empty;
try
{
ConfigurationSectionGroup sectionGroup = config.GetSectionGroup("logonurls");
System.Xml.XmlDocument doc = new System.Xml.XmlDocument();
doc.LoadXml(sectionGroup);
foreach (System.Xml.XmlNode node in doc.ChildNodes)
{
// I want to loop through all the settings element of the section
Console.WriteLine(node.Value);
}
}
catch (Exception e)
{
}
return rtnValue;
}
简单提醒一下:如果将其转换为XML,还可以使用XPath来获取值。
System.Xml.XmlNode element = doc.SelectSingleNode("/NODE");