如何在Web Api中使用响应Ok的Httpclient获取对象

本文关键字：Ok 响应 Httpclient 取对象 获取 Web Api | 更新日期: 2023-09-27 18:04:28

my web API like 

    public async Task<IHttpActionResult> RegisterUser(User user)
    {
        //User Implementation here
        return Ok(user);
    }

我使用HTTPClient请求web api如下所述。

var client = new HttpClient();
string json = JsonConvert.SerializeObject(model);
var result = await client.PostAsync( "api/users", new StringContent(json, Encoding.UTF8, "application/json"));

在哪里我可以找到用户对象在我的结果请求是在客户端应用程序上实现的?

如何在Web Api中使用响应Ok的Httpclient获取对象

您可以使用(取决于您需要什么)，并将其反序列化回用户对象。

await result.Content.ReadAsByteArrayAsync();
//or
await result.Content.ReadAsStreamAsync();
//or
await result.Content.ReadAsStringAsync();

如果你的web api返回JSON，你可以使用

var user = JsonConvert.DeserializeObject<User>( await result.Content.ReadAsStringAsync());

编辑:正如cordan所指出的，您还可以添加对System.Net.Http.Formatting的引用并使用:

await result.Content.ReadAsAsync<User>()

string Baseurl = GetBaseUrl(microService);
string url = "/client-api/api/token";
using (HttpClient client = new HttpClient())`enter code here`
{
    client.BaseAddress = new Uri(Baseurl);
    client.DefaultRequestHeaders.Clear();
    client.DefaultRequestHeaders.TryAddWithoutValidation("Content-Type", "application/x-www-form-urlencoded");
    List<KeyValuePair<string, string>> keyValues = new List<KeyValuePair<string, string>>();
    keyValues.Add(new KeyValuePair<string, string>("client_id", "5196810"));
    keyValues.Add(new KeyValuePair<string, string>("grant_type", "password"));
    keyValues.Add(new KeyValuePair<string, string>("username", "abc.a@gmail.com"));
    keyValues.Add(new KeyValuePair<string, string>("password", "Sonata@123"));
    keyValues.Add(new KeyValuePair<string, string>("platform", "FRPWeb"));

    HttpContent content = new FormUrlEncodedContent(keyValues);
    content.Headers.ContentType = new MediaTypeHeaderValue("application/x-www-form-urlencoded");
    content.Headers.ContentType.CharSet = "UTF-8";
    var result = client.PostAsync(url, content).Result;
    string resultContent = result.Content.ReadAsStringAsync().Result;
}
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