当IActionResult类型返回结果时,如何在Xunit中获取内容值
本文关键字:Xunit 获取 类型 IActionResult 返回 结果 | 更新日期: 2023-09-27 18:06:03
我有一个使用Xunit的单元测试项目,我们正在测试的方法返回IActionResult
。
我看到一些人建议使用"NegotiatedContentResult"来获取IActionResult
的内容,但这在Xunit中不起作用。
所以我想知道如何在Xunit中获得一个IActionResult
的内容值?
public void GetTest()
{
var getTest = new ResourcesController(mockDb);
var result = getTest.Get("1");
//Here I want to convert the result to my model called Resource and
//compare the attribute Description like below.
Resource r = ?? //to get the content value of the IActionResult
Assert.Equal("test", r.Description);
}
有人知道如何在XUnit中做到这一点吗?
取决于您期望返回的内容。在前面的示例中,您使用了如下操作:
[HttpGet("{id}")]
public IActionResult Get(string id) {
var r = unitOfWork.Resources.Get(id);
unitOfWork.Complete();
Models.Resource result = ConvertResourceFromCoreToApi(r);
if (result == null) {
return NotFound();
} else {
return Ok(result);
}
}
该方法将返回OkObjectResult
或NotFoundResult
。如果测试中的方法期望返回Ok()
,那么您需要将测试中的结果强制转换为您期望的结果,然后在
public void GetTest_Given_Id_Should_Return_OkObjectResult_With_Resource() {
//Arrange
var expected = "test";
var controller = new ResourcesController(mockDb);
//Act
var actionResult = controller.Get("1");
//Assert
var okObjectResult = actionResult as OkObjectResult;
Assert.NotNull(okObjectResult);
var model = okObjectResult.Value as Models.Resource;
Assert.NotNull(model);
var actual = model.Description;
Assert.Equal(expected, actual);
}
上面的解决方案给出了一个CS0039在.NET7.0
可能的解决方案:
// Arrange
var expected = "test";
var controller = new ResourcesController(mockDb);
// Act
var actionResult = controller.Get("1");
// Assert
actionResult.Should().NotBeNull();
actionResult.Result.Should().BeOfType<OkObjectResult>();
var model = (actionResult.Result as OkObjectResult)!.Value as string;
model.Should().NotBeNull();
model.Should().BeEquivalentTo(expected);