Treeview在web表单中检查子节点对父节点的检查
本文关键字:检查 子节点 父节点 web 表单 Treeview | 更新日期: 2023-09-27 18:06:19
我使用System.Web.UI类的Treeview控件来显示项目的类别和子类别。
我试过下面的代码,但没有希望
protected void tvwOrganisation_TreeNodeCheckChanged(object sender, TreeNodeEventArgs e)
{
if (tvwOrganisation.CheckedNodes.Count > 0)
{
// the selected nodes.
foreach (TreeNode node in tvwOrganisation.CheckedNodes)
{
if (node.ChildNodes.Count > 0)
{
foreach (TreeNode childNode in node.ChildNodes)
{
childNode.Checked = true;
}
}
}
}
}
有办法我可以做到这一点,我也试过javascript。
还有在web表单中如何替换AfterCheck - windows窗体事件
树标签如下,
<asp:TreeView ID="tvwRegionCountry" runat="server" ShowCheckBoxes="All" ExpandDepth="0" AfterClientCheck="CheckChildNodes();" PopulateNodesFromClient="true" ShowLines="true" ShowExpandCollapse="true" OnTreeNodeCheckChanged="tvwRegionCountry_TreeNodeCheckChanged"
onclick="OnTreeClick(event)">
</asp:TreeView>
在asp.net树视图复选框选择中添加了以下JS
<script language="javascript" type="text/javascript">
function OnTreeClick(evt) {
var src = window.event != window.undefined ? window.event.srcElement : evt.target;
var isChkBoxClick = (src.tagName.toLowerCase() == "input" && src.type == "checkbox");
if (isChkBoxClick) {
var parentTable = GetParentByTagName("table", src);
var nxtSibling = parentTable.nextSibling;
if (nxtSibling && nxtSibling.nodeType == 1)//check if nxt sibling is not null & is an element node
{
if (nxtSibling.tagName.toLowerCase() == "div") //if node has children
{
//check or uncheck children at all levels
CheckUncheckChildren(parentTable.nextSibling, src.checked);
}
}
//check or uncheck parents at all levels
CheckUncheckParents(src, src.checked);
}
}
function CheckUncheckChildren(childContainer, check) {
var childChkBoxes = childContainer.getElementsByTagName("input");
var childChkBoxCount = childChkBoxes.length;
for (var i = 0; i < childChkBoxCount; i++) {
childChkBoxes[i].checked = check;
}
}
function CheckUncheckParents(srcChild, check) {
var parentDiv = GetParentByTagName("div", srcChild);
var parentNodeTable = parentDiv.previousSibling;
if (parentNodeTable) {
var checkUncheckSwitch;
if (check) //checkbox checked
{
var isAllSiblingsChecked = AreAllSiblingsChecked(srcChild);
if (isAllSiblingsChecked)
checkUncheckSwitch = true;
else
return; //do not need to check parent if any(one or more) child not checked
}
else //checkbox unchecked
{
checkUncheckSwitch = false;
}
var inpElemsInParentTable = parentNodeTable.getElementsByTagName("input");
if (inpElemsInParentTable.length > 0) {
var parentNodeChkBox = inpElemsInParentTable[0];
parentNodeChkBox.checked = checkUncheckSwitch;
//do the same recursively
CheckUncheckParents(parentNodeChkBox, checkUncheckSwitch);
}
}
}
function AreAllSiblingsChecked(chkBox) {
var parentDiv = GetParentByTagName("div", chkBox);
var childCount = parentDiv.childNodes.length;
for (var i = 0; i < childCount; i++) {
if (parentDiv.childNodes[i].nodeType == 1) //check if the child node is an element node
{
if (parentDiv.childNodes[i].tagName.toLowerCase() == "table") {
var prevChkBox = parentDiv.childNodes[i].getElementsByTagName("input")[0];
//if any of sibling nodes are not checked, return false
if (!prevChkBox.checked) {
return false;
}
}
}
}
return true;
}
//utility function to get the container of an element by tagname
function GetParentByTagName(parentTagName, childElementObj) {
var parent = childElementObj.parentNode;
while (parent.tagName.toLowerCase() != parentTagName.toLowerCase()) {
parent = parent.parentNode;
}
return parent;
}
</script>