MVC 4.0 - Xml to model

本文关键字：to model Xml MVC | 更新日期: 2023-09-27 18:11:28

我有一个返回xml的系统，我需要构建一些使用这些数据的MVC页面。我使用MVC 4.0和c# FW4.0。我像这样填充我的模型:

List<PersonName> tmpList = new List<PersonName>();
IEnumerable<PersonName> PeopleNames = tmpList;                
XDocument oDoc = XDocument.Parse(sResponse);
var vPeopleNames = from c in oDoc.Descendants("PersonName")
                   select new PersonName()
                   {
                       PersonID = (string)c.Element("PersonID"),                                 
                       FirstName = (string)c.Element("FirstName"),
                       LastName = (string)c.Element("LastName")
                   };
PeopleNames = vPeopleNames;
var oModel = PeopleNames;           
return View("PeopleNamesList", PeopleNames);

我想知道是否有一种方法可以自动做到这一点。我不想指定"PersonID"、"FirstName"answers"LastName"字段的名称。如果我有50个字段，这将是太痛苦了…

MVC 4.0 - Xml to model

可以借助XNode.CreateReader()和XContainer.CreateWriter()从XmlSerializer序列化到XElement。以下扩展方法可以完成这项工作:

public static class XObjectExtensions
{
    public static T Deserialize<T>(this XContainer element, XmlSerializer serializer = null)
    {
        using (var reader = element.CreateReader())
        {
            object result = (serializer ?? new XmlSerializer(typeof(T))).Deserialize(reader);
            if (result is T)
                return (T)result;
        }
        return default(T);
    }
    public static XmlSerializerNamespaces NoStandardXmlNamespaces()
    {
        var ns = new XmlSerializerNamespaces();
        ns.Add("", ""); // Disable the xmlns:xsi and xmlns:xsd attributes.
        return ns;
    }
    public static XElement SerializeToXElement<T>(this T obj)
    {
        return obj.SerializeToXElement(null, NoStandardXmlNamespaces()); // Disable the xmlns:xsi and xmlns:xsd attributes by default.
    }
    public static XElement SerializeToXElement<T>(this T obj, XmlSerializerNamespaces ns)
    {
        return obj.SerializeToXElement(null, ns);
    }
    public static XElement SerializeToXElement<T>(this T obj, XmlSerializer serializer, bool omitStandardNamespaces)
    {
        return obj.SerializeToXElement(serializer, (omitStandardNamespaces ? NoStandardXmlNamespaces() : null));
    }
    public static XElement SerializeToXElement<T>(this T obj, XmlSerializer serializer, XmlSerializerNamespaces ns)
    {
        var doc = new XDocument();
        using (var writer = doc.CreateWriter())
            (serializer ?? new XmlSerializer(obj.GetType())).Serialize(writer, obj, ns);
        var element = doc.Root;
        if (element != null)
            element.Remove();
        return element;
    }
}

然后像这样使用:

        var vPeopleNames = (from c in oDoc.Descendants("PersonName")
                            select c.Deserialize<PersonName>()).ToList();
        var peopleXml = vPeopleNames.SerializeToXElement(); // Creates a root element named <ArrayOfPersonName> containing all people names as child elements.

PersonName类定义如下:

public class PersonName
{
    public string PersonID { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
}
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