字符数组转换为二维整数数组失败

本文关键字:数组 二维 失败 整数 转换 字符 | 更新日期: 2023-09-27 18:12:57

我似乎有麻烦将字符数组转换为2D整数数组。具体情况如下:

我想将包含特定分隔符的字符数组转换为多维数组,其中每行的末尾由字符数组内的分隔符指定(我已经在不同的方法中确保每行具有相同的长度)。

数组中只包含0和1。

问题是,当测试方法时,它(方法)似乎跳过了一行-读取第一行,下一行是0,读取第三行,第四行是0。

这些是方法(所讨论的方法和测试方法):

    /// <summary>
    /// Converts a character array to 2D int array, where each character is a digit and only the digits of 1 and 0 are 
    /// allowed.
    /// </summary>
    /// <returns>The 2D int array.</returns>
    /// <param name="charArray">Character array.</param>
    /// <param name="delimiter">Delimiter.</param>
    public int[,] ConvertCharArrayTo2DIntArray(char[] charArray, char delimiter){
        int columnCounter = 0;
        //count how many rows
        while (charArray [columnCounter] != delimiter) {
            columnCounter++;
        }
        //count how many lines taking into account the delimiter
        int rows = charArray.Length/(columnCounter+1);
        int[,] twoDimArray = new int[rows, columnCounter];
        //count
        int h = 0;
        for (int i = 0; i < rows; i++) {
            for (int j = 0; j < columnCounter; j++) {
                if (charArray [h] != ''n') {
                    twoDimArray [i, j] = (int)Char.GetNumericValue(charArray [h]);
                    //throw exception if the array contains numbers other than 1 or 0
                    if (twoDimArray [i, j] != 1 && twoDimArray [i, j] != 0)
                        throw new ArgumentException ();
                    h++;
                } else {
                    h++;
                    break;
                }
            }
        }
        return twoDimArray;
    }

这是测试方法:

    [Test()]
    public void TestConvertCharArrayTo2DIntArray(){
        HelperClass hc = new HelperClass ();
        int[,] twoDimArrayExpected = new int[,]{ 
            { 0, 1, 0, 1, 0 },
            { 0, 1, 0, 1, 0 },
            { 0, 1, 0, 1, 0 },
            { 0, 1, 0, 1, 0 } };
        char[] charArray = new char[] {'0','1','0','1','1',''n','1','1','1','1','1',''n','0','1','1','1','0',''n','0','1','0','1','0',''n'};
        int[,] twoDimArrayActual = hc.ConvertCharArrayTo2DIntArray (charArray, ''n');
        for (int i = 0; i < twoDimArrayExpected.GetLength (0); i++) {
            for (int j = 0; j < twoDimArrayExpected.GetLength (1); j++) {
                Console.Write (twoDimArrayActual [i,j]);
                //Commented out because it throws exceptions                                 
                //Assert.AreEqual(twoDimArrayExpected[i,j],
                //twoDimArrayActual[i,j]);
                if (j == twoDimArrayExpected.GetLength (1) - 1) {
                    Console.Write ("'n");
                }
            }
        }
    }

输出如下:

01011年

00000年

11111年

00000年

我可能只是被卡住了,但现在我真的想不出来。

字符数组转换为二维整数数组失败

当内部循环结束时,您将定位在分隔符上。此时需要跳过字符分隔符,使控制变量h

递增

就像你现在做的那样,你增加控制变量,但是你跳出了内部循环。然而,仅仅删除break指令不起作用,因为退出内循环会使外循环的控制变量i增加,使每个偶数行都为空且未处理

你可以试着用

修复你的代码
int h = 0;
for (int i = 0; i < rows; i++)
{
    for (int j = 0; j < columnCounter; j++)
    {
        twoDimArray[i, j] = (int)Char.GetNumericValue(charArray[h]);
        //throw exception if the array contains numbers other than 1 or 0
        if (twoDimArray[i, j] != 1 && twoDimArray[i, j] != 0)
            throw new ArgumentException();
        h++;
    }
    h++;
}

如果使用列表对象,这很简单

 List<List<int>> twoDimArrayExpected = new List<List<int>>() { 
               new List<int>() { 0, 1, 0, 1, 0 },
               new List<int>(){ 0, 1, 0, 1, 0 },
               new List<int>(){ 0, 1, 0, 1, 0 },
               new List<int>(){ 0, 1, 0, 1, 0 } };
            string resutls = string.Join("'n", twoDimArrayExpected.Select(x => string.Join("", x)));​