如何反序列化具有动态(数字)键名的子对象

本文关键字：对象 数字 反序列化 动态 | 更新日期: 2023-09-27 18:13:03

我如何反序列化这个JSON数据?键"100034"等在本质上是动态的。

{
    "users" : {
        "100034" : {
            "name"  : "tom",
            "state" : "WA",
            "id"    : "cedf-c56f-18a4-4b1"
        },
        "10045" : {
            "name"  : "steve",
            "state" : "NY",
            "id"    : "ebb2-92bf-3062-7774"
        },
        "12345" : {
            "name"  : "mike",
            "state" : "MA",
            "id"    : "fb60-b34f-6dc8-aaf7"
        }
    }
}

是否有一种方法可以直接访问具有名称，状态和Id的每个对象?

如何反序列化具有动态(数字)键名的子对象

对于具有可变属性名的JSON对象，您可以使用Dictionary<string, T>代替常规类，其中T是表示项数据的类。

这样声明你的类:

class RootObject
{
    public Dictionary<string, User> users { get; set; }
}
class User
{
    public string name { get; set; }
    public string state { get; set; }
    public string id { get; set; }
}

然后这样反序列化:

RootObject obj = JsonConvert.DeserializeObject<RootObject>(json);
演示:

class Program
{
    static void Main(string[] args)
    {
        string json = @"
        {
            ""users"": {
                ""10045"": {
                    ""name"": ""steve"",
                    ""state"": ""NY"",
                    ""id"": ""ebb2-92bf-3062-7774""
                },
                ""12345"": {
                    ""name"": ""mike"",
                    ""state"": ""MA"",
                    ""id"": ""fb60-b34f-6dc8-aaf7""
                },
                ""100034"": {
                    ""name"": ""tom"",
                    ""state"": ""WA"",
                    ""id"": ""cedf-c56f-18a4-4b1""
                }
            }
        }";
        RootObject root = JsonConvert.DeserializeObject<RootObject>(json);
        foreach (string key in root.users.Keys)
        {
            Console.WriteLine("key: " + key);
            User user = root.users[key];
            Console.WriteLine("name: " + user.name);
            Console.WriteLine("state: " + user.state);
            Console.WriteLine("id: " + user.id);
            Console.WriteLine();
        }
    }
}
输出:

key: 10045
name: steve
state: NY
id: ebb2-92bf-3062-7774
key: 12345
name: mike
state: MA
id: fb60-b34f-6dc8-aaf7
key: 100034
name: tom
state: WA
id: cedf-c56f-18a4-4b1

  1. 添加package System.Web.Script.Serialization;

  2. 假设您的JSON包含Internet用户列表，我创建一个这样的类。

    public class internet
{
   public List<User> Users { get; set; }
};
public class User
{
   public String Name { get; set; }
   public String Id { get; set; }
   public String State { get; set; }
};

假设你的JSON字符串在变量'JSONDATA'中，按照下面的代码将JSON数据DE序列化到Class对象。

     var JSONDATA = /* Your JSON String */;
     JavaScriptSerializer serializer = new JavaScriptSerializer();
     internet Intr = serializer.Deserialize<internet>(JSONDATA);
相关文章：