背景

假设我有一个Address对象：

public class Address_Model{
     public int Id {get; set;}
     public string Street{get; set;}
     public string City {get; set;}
     public string State {get; set;}
     public string PostalCode{get; set;}
}

此属性用于其他几个对象(即office对象、home对象等(：

public class Office_Model{
     public int Id {get; set;}
     public Address_Model Address{get; set;}
     //. . . (other properties specific to the office model)
}
public class Home_Model{
     public int Id {get; set;}
     public Address_Model Address{get; set;}
     //. . . (other properties specific to the home model)
}

这些模特住在我的BLL里。在使用DAL数据的构造函数中，我目前手动构造Address属性：

public Office_Model GetOffice(int id){
var office = DAL.SomeClass.GettOfficeById(id);
return new Office_Model
{
   Id = office.Id,
   Address = new Address_Model{
       Id = office.Address.Id,
       Street = office.Address.Street,
       City = office.Address.City,
       State = office.Address.State,
       PostalCode = office.Address.PostalCode
   }
}
}
public Home_Model GetHome(int id){
var home = DAL.SomeClass.GettHomeById(id);
return new Home_Model
{
   Id = home.Id,
   Address = new Address_Model{
       Id = home.Address.Id,
       Street = home.Address.Street,
       City = home.Address.City,
       State = home.Address.State,
       PostalCode = home.Address.PostalCode
   }
}
}

为了提高代码的可维护性(例如，不必在构造Address_Model的所有地方添加像Street2这样的新属性(，我想创建一种构造地址模型的通用方法：

public Address_Model GetAddressModel(DAL.SomeClass.Address address){
     return new Address_Model{
           Id = address.Address.Id,
           Street = address.Address.Street,
           City = address.Address.City,
           State = address.Address.State,
           PostalCode = address.Address.PostalCode
     }
}

现在我的BLL getter方法看起来更像这样：

  public Office_Model GetOffice(int id){
    var office = DAL.SomeClass.GettOfficeById(id);
    return new Office_Model
    {
       Id = office.Id,
       Address = GetAddressModel(office.Address);
    }
    }
    public Home_Model GetHome(int id){
    var home = DAL.SomeClass.GettHomeById(id);
    return new Home_Model
    {
       Id = home.Id,
       Address = GetAddressModel(home.Address);
    }
    }

问题

委托该施工作业会对绩效产生负面影响吗？我是性能评测的新手，刚刚了解了boxing和unboxing；我不确定这种类型的性能下降是否适用于我在这里所做的工作。

显然，我已经在很大程度上简化了这个例子。事实上，还有更多的嵌套对象需要构建。