Protobuf-net仅使用getter序列化属性失败-无法对属性应用更改
本文关键字:属性 应用 失败 getter 序列化 Protobuf-net | 更新日期: 2023-09-27 18:15:14
我正在使用protobuf-net序列化一个对象,我得到异常:
不能应用更改属性TestProject.TestMessage.ClientId
与加亮:at ProtoBuf.Serializers.PropertyDecorator.SanityCheck(TypeModel model, PropertyInfo property, IProtoSerializer tail, Boolean& writeValue, Boolean nonPublic, Boolean allowInternal)
at ProtoBuf.Serializers.PropertyDecorator..ctor(TypeModel model, Type forType, PropertyInfo property, IProtoSerializer tail)
at ProtoBuf.Meta.ValueMember.BuildSerializer()
at ProtoBuf.Meta.ValueMember.get_Serializer()
at ProtoBuf.Meta.MetaType.BuildSerializer()
at ProtoBuf.Meta.MetaType.get_Serializer()
at ProtoBuf.Meta.RuntimeTypeModel.Serialize(Int32 key, Object value, ProtoWriter dest)
at ProtoBuf.Meta.TypeModel.SerializeCore(ProtoWriter writer, Object value)
at ProtoBuf.Meta.TypeModel.Serialize(Stream dest, Object value, SerializationContext context)
at ProtoBuf.Meta.TypeModel.Serialize(Stream dest, Object value)
at ProtoBuf.Serializer.Serialize[T](Stream destination, T instance)
我的班级如下:
[DataContract]
public class TestMessage
{
private int clientId;
[DataMember(Order = 1)]
public int ClientId
{
get { return clientId; }
}
private string name;
[DataMember(Order = 2)]
public string Name
{
get { return name; }
}
public TestMessage(int clientId,
string name)
{
this.clientId = clientId;
this.name =name;
}
}
是的,这是正确的:protobuf-net不能成功往返get-only属性,例如您的ClientId
,因此将抛出一个异常,试图构建一个显式要求序列化此类属性的合约。
它并不是唯一有这种限制的。我注意到你正在用数据契约属性标记你的类型。如果我尝试用DataContractSerializer
序列化它的一个实例,它会失败,并产生一个等效的异常:
System.Runtime.Serialization.InvalidDataContractException was caught
Message="No set method for property 'ClientId' in type 'Question40276317.V1.TestMessage'."
Source="System.Runtime.Serialization"
如果你只是想跳过get-only属性,那么用[IgnoreDataMember]
标记它们。如果您想成功地序列化和反序列化它们,您有以下选项:
首先,protobuf-net需要能够构造你的对象。与Json。NET不会调用参数化构造函数,所以最简单的方法是添加无参数构造函数。只要它存在,它就可以是私有的或受保护的(在完整框架上)。或者,您可以设置[ProtoContract(SkipConstructor = true)]
,但是这并不适用于所有框架或部分信任的情况。
[DataContract]
public class TestMessage
{
private int clientId;
[DataMember(Order = 1)]
public int ClientId
{
get { return clientId; }
private set { clientId = value; }
}
private string name;
[DataMember(Order = 2)]
public string Name
{
get { return name; }
private set { name = value; }
}
protected TestMessage() { }
public TestMessage(int clientId, string name)
{
this.clientId = clientId;
this.name = name;
}
}
另一种方法是用数据契约属性标记底层字段而不是属性:
[DataContract]
public class TestMessage
{
[DataMember(Name = "ClientId", Order = 1)]
private int clientId;
public int ClientId
{
get { return clientId; }
}
[DataMember(Name = "Name", Order = 2)]
private string name;
public string Name
{
get { return name; }
}
protected TestMessage() { }
public TestMessage(int clientId, string name)
{
this.clientId = clientId;
this.name = name;
}
}
或者,如果您真的希望clientId
和name
的值在构造之后是不可变的,那么您将需要一个序列化代理,如下所示:
public class TestMessage
{
private readonly int clientId;
public int ClientId
{
get { return clientId; }
}
private readonly string name;
public string Name
{
get { return name; }
}
public TestMessage(int clientId, string name)
{
this.clientId = clientId;
this.name = name;
}
}
[DataContract]
internal class TestMessageSurrogate
{
public static implicit operator TestMessageSurrogate(TestMessage message)
{
if (message == null)
return null;
return new TestMessageSurrogate { ClientId = message.ClientId, Name = message.Name };
}
public static implicit operator TestMessage(TestMessageSurrogate message)
{
if (message == null)
return null;
return new TestMessage(message.ClientId, message.Name);
}
[DataMember(Order = 1)]
public int ClientId { get; set; }
[DataMember(Order = 2)]
public string Name { get; set; }
}
那么,在序列化之前,执行:
ProtoBuf.Meta.RuntimeTypeModel.Default.Add(typeof(TestMessage), true).SetSurrogate(typeof(TestMessageSurrogate));
通过使用代理,您还可以避免使用任何无参数的构造函数。