字符串错误.在创建多维数组时连接
本文关键字:数组 连接 错误 创建 字符串 | 更新日期: 2023-09-27 18:17:11
我创建了一个多维数组:
string[,] array_questions = new string[dt.Rows.Count, dt.Columns.Count];
for (i = 0; i < dt.Rows.Count; i++)
{
for (j = 0; j < dt.Columns.Count; j++)
{
array_questions[i, j] = dt.Rows[i][j].ToString();
//Response.Write(array_questions[i, j]);
}
// Response.Write(Environment.NewLine);
//Response.Write("'n");
}
foreach (string number in array_questions)
{
//Response.Write(number + " ");
//Response.Write(Environment.NewLine);
Response.Write(string.Join(", ", number) + Environment.NewLine);
}
,但它显示了如下错误:错误1最佳重载方法匹配'string '。Join(string, string[])'有一些无效参数。请帮助
不需要for循环来连接字符串。
string.Join(", ", array_questions)
替换代码
foreach (string number in array_questions)
{
//Response.Write(number + " ");
//Response.Write(Environment.NewLine);
Response.Write(string.Join(", ", number) + Environment.NewLine);
}
Response.Write(string.Join(", ", array_questions) + Environment.NewLine);
您需要扁平化您的数组来使用string.Join
。它接受分隔符和一个单维数组,因此您可能需要这样做。但不确定你想要达到什么目的。您正试图将string.Join(string, string[])
呼叫为string.Join(string, string)
试试这样写:
var sdArray= new List<string>();
for (var i = 0; i < dt.Rows.Count; i++) //Get the length of first Dimension
{
for (var j = 0; j < dt.Columns.Count; j++) //Get the length of second Dimension
{
sdArray.Add(array_questions[i, j]);
}
}
///
Response.Write(string.Join(", ", sdArray) + Environment.NewLine);
使用Linq可以更好地平化这些。
像这样
string joinedSetOfQns= string.Join(",",
Enumerable.Range(0, dt.Rows.Count)
.SelectMany(i => Enumerable.Range(0, dt.Columns.Count)
.Select(j => array_questions[i, j])));
Response.Write(joinedSetOfQns + Environment.NewLine);
这是string的定义。加入
public static string Join(
string separator,
params string[] value /// <-- Takes single Dimensional Array not a string.
)
更新:因为你需要加入Rowwise
for (var i = 0; i < dt.Rows.Count; i++)
{
var result = new List<string>();
for (var j = 0; j < dt.Columns.Count; j++)
{
result.Add(array_questions[i, j]);
}
Response.Write(string.Join(", ", result) + Environment.NewLine);
}