需要帮助来连接数组中的项

本文关键字：数组 连接 帮助 | 更新日期: 2023-09-27 18:02:12

我需要帮助连接数组中长度为1的两个或多个连续项。

例如，我想修改这个:

string[] str = { "one", "two", "three","f","o","u","r" };

: 

str = {"one","two","three","four"};

需要帮助来连接数组中的项

使用GroupAdjacent扩展名(例如这里列出的扩展名)，您可以执行以下操作:

string[] input = ...
string[] output = input.GroupAdjacent(item => item.Length == 1)
                       .SelectMany(group => group.Key 
                                          ? new[] { string.Concat(group) } 
                                          : group.AsEnumerable())
                      .ToArray();

如果效率是一个大问题，我建议滚动你自己的迭代器块或类似的

这是我的答案，在LINQPad中使用:)

void Main()
{
    string[] str = { "one", "two", "three","f","o","u","r","five" };
    string[] newStr = Algorithm(str).ToArray();
    newStr.Dump();
}
public static IEnumerable<string> Algorithm(string[] str)
{
       string text = null;
       foreach(var item in str)
       {
        if(item.Length > 1)
        {
            if(text != null)
            {
                yield return text;
                text = null;
            }
            yield return item;
        }
        else
            text += item;
        }
        if(text != null)
            yield return text;
}
输出:

一个
两个
三
四
5

我认为最简单、最有效的方法就是遍历数组:

string[] str = { "one", "two", "three", "f", "o", "u", "r" };
List<string> output = new List<string>();
StringBuilder builder = null;
bool merge = false;
foreach(string item in str)
{
    if (item.Length == 1)
    {
        if (!merge)
        {
            merge = true;
            builder = new StringBuilder();
        }
        builder.Append(item);
    }
    else
    {
        if (merge)
            output.Add(merge.ToString());
        merge = false;
        output.Add(item);
    }
}
if (merge)
    output.Add(builder.ToString());

应该这样做:

    private string[] GetCombined(string[] str)
    {
        var combined = new List<string>();
        var temp = new StringBuilder();
        foreach (var s in str)
        {
            if (s.Length > 1)
            {
                if (temp.Length > 0)
                {
                    combined.Add(temp.ToString());
                    temp = new StringBuilder();
                }
                combined.Add(s);
            }
            else
            {
                temp.Append(s);
            }
        }
        if (temp.Length > 0)
        {
            combined.Add(temp.ToString());
            temp = new StringBuilder();
        }
        return combined.ToArray();
    }

你可以这样做:

string[] str = { "one", "two", "three", "f", "o", "u", "r" };
var result = new List<string>();
int i = 0;
while (i < str.Length) {
    if (str[i].Length == 1) {
        var sb = new StringBuilder(str[i++]);
        while (i < str.Length && str[i].Length == 1) {
            sb.Append(str[i++]);
        }
        result.Add(sb.ToString());
    } else {
        result.Add(str[i++]);
    }
}
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