获取作为lambda表达式传递的参数的PropertyInfo

本文关键字:参数 PropertyInfo 表达式 lambda 获取 | 更新日期: 2023-09-27 18:18:40

例如,我有一个类:

public class Person
{
  public int Id;
  public string Name, Address;
}

,我想调用一个方法来更新这个类的信息,基于Id:

update(myId, myPerson => myPerson.Name = "abc");

explain:该方法将从数据库中查询并获得给定myIdPerson实体,然后将Name设置为"abc",因此它做的工作与我调用的相同:

update(myId, myPerson => myPerson.Address = "my address");

是可能的吗?如果有,那是怎么回事?

获取作为lambda表达式传递的参数的PropertyInfo

我不会使用PropertyInfo,就像Reed Copsey在他的回答中所说的那样,但只是为了方便,您可以这样提取表达式的PropertyInfo:

public PropertyInfo GetPropertyFromExpression<T>(Expression<Func<T, object>> GetPropertyLambda)
{
    MemberExpression Exp = null;
    //this line is necessary, because sometimes the expression comes in as Convert(originalexpression)
    if (GetPropertyLambda.Body is UnaryExpression)
    {
        var UnExp = (UnaryExpression)GetPropertyLambda.Body;
        if (UnExp.Operand is MemberExpression)
        {
            Exp = (MemberExpression)UnExp.Operand;
        }
        else
            throw new ArgumentException();
    }
    else if (GetPropertyLambda.Body is MemberExpression)
    {
        Exp = (MemberExpression)GetPropertyLambda.Body;
    }
    else
    {
        throw new ArgumentException();
    }
    return (PropertyInfo)Exp.Member;
}

对于像MyPerson.PersonData.PersonID这样的复合表达式,您可以继续获取子表达式,直到它们不再是MemberExpressions为止。

public PropertyInfo GetPropertyFromExpression<T>(Expression<Func<T, object>> GetPropertyLambda)
{
    //same body of above method without the return line.
    //....
    //....
    //....
    var Result = (PropertyInfo)Exp.Member;
    var Sub = Exp.Expression;
    while (Sub is MemberExpression)
    {
        Exp = (MemberExpression)Sub;
        Result = (PropertyInfo)Exp.Member;
        Sub = Exp.Expression;
    }
    return Result;
    //beware, this will return the last property in the expression.
    //when using GetValue and SetValue, the object needed will not be
    //the first object in the expression, but the one prior to the last.
    //To use those methods with the first object, you will need to keep
    //track of all properties in all member expressions above and do
    //some recursive Get/Set following the sequence of the expression.
}

这是可能的,并且不需要使用PropertyInfo

你可以这样设计你的方法:

public bool Update<T>(int id, Action<T> updateMethod)
    // where T  : SomeDbEntityType
{
    T entity = LoadFromDatabase(id); // Load your "person" or whatever
    if (entity == null) 
        return false; // If you want to support fails this way, etc...
    // Calls the method on the person
    updateMethod(entity);
    SaveEntity(entity); // Do whatever you need to persist the values
    return true;
}

以下是针对现代语法更新的@DanielMöller答案版本,带有指定的异常消息和文档。

/// <summary>
///     Gets the corresponding <see cref="PropertyInfo" /> from an <see cref="Expression" />.
/// </summary>
/// <param name="property">The expression that selects the property to get info on.</param>
/// <returns>The property info collected from the expression.</returns>
/// <exception cref="ArgumentNullException">When <paramref name="property" /> is <c>null</c>.</exception>
/// <exception cref="ArgumentException">The expression doesn't indicate a valid property."</exception>
private PropertyInfo GetPropertyInfo<T, P>(Expression<Func<T, P>> property)
{
    if (property == null) {
        throw new ArgumentNullException(nameof(property));
    }
    if (property.Body is UnaryExpression unaryExp) {
        if (unaryExp.Operand is MemberExpression memberExp) {
            return (PropertyInfo)memberExp.Member;
        }
    }
    else if (property.Body is MemberExpression memberExp) {
        return (PropertyInfo)memberExp.Member;
    }
    throw new ArgumentException($"The expression doesn't indicate a valid property. [ {property} ]");
}

更干净的IMHO (@DanielMöller帖子的另一个变体)

        /// <summary>
        ///     Gets the corresponding <see cref="PropertyInfo" /> from an <see cref="Expression" />.
        /// </summary>
        /// <param name="expression">The expression that selects the property to get info on.</param>
        /// <returns>The property info collected from the expression.</returns>
        /// <exception cref="ArgumentNullException">When <paramref name="expression" /> is <c>null</c>.</exception>
        /// <exception cref="ArgumentException">The expression doesn't indicate a valid property."</exception>
        public static PropertyInfo GetPropertyInfo<T>(this Expression<Func<T, object>> expression)
        {
            switch (expression?.Body) {
                case null:
                    throw new ArgumentNullException(nameof(expression));
                case UnaryExpression unaryExp when unaryExp.Operand is MemberExpression memberExp:
                    return (PropertyInfo)memberExp.Member;
                case MemberExpression memberExp:
                    return (PropertyInfo)memberExp.Member;
                default:
                    throw new ArgumentException($"The expression doesn't indicate a valid property. [ {expression} ]");
            }
        }

使用c# 9的开关表达式

public static PropertyInfo GetPropertyInfo<T>(this Expression<Func<T, object>> expression) =>
    expression?.Body switch
    {
        null => throw new ArgumentNullException(nameof(expression)),
        UnaryExpression ue when ue.Operand is MemberExpression me => (PropertyInfo)me.Member,
        MemberExpression me => (PropertyInfo)me.Member,
        _ => throw new ArgumentException($"The expression doesn't indicate a valid property. [ {expression} ]")
    };