用逗号分割字符串,忽略引号中的任何标点符号(包括',')
本文关键字:标点符号 任何 包括 字符串 分割 | 更新日期: 2023-09-27 18:19:12
如何通过逗号来分割字符串(从文本框),不包括双引号中的 (而不去掉引号),以及其他可能的标点符号(例如:"。’;' ' - ' ')?
。如果有人在文本框中输入了以下内容:
apple, orange, "baboons, cows", rainbow, "unicorns, gummy bears"
我如何将上面的字符串分成下面的字符串(比如,分成一个List)?
apple
orange
"baboons, cows"
rainbow
"Unicorns, gummy bears..."
谢谢你的帮助!
你可以试试下面的正则表达式,
string value = @"apple, orange, ""baboons, cows"", rainbow, ""unicorns, gummy bears""";
string[] lines = Regex.Split(value, @", (?=(?:""[^""]*?(?: [^""]*)*))|, (?=[^"",]+(?:,|$))");
foreach (string line in lines) {
Console.WriteLine(line);
}
输出:apple
orange
"baboons, cows"
rainbow
"unicorns, gummy bears"
IDEONE
试试这个:
Regex str = new Regex("(?:^|,)('"(?:[^'"]+|'"'")*'"|[^,]*)", RegexOptions.Compiled);
foreach (Match m in str.Matches(input))
{
Console.WriteLine(m.Value.TrimStart(','));
}
你也可以试着看看FileHelpers
与CSV解析器(而不是Regex)非常相似,您可以遍历每个字符,如下所示:
public List<string> ItemStringToList(string inputString)
{
var itemList = new List<string>();
var currentIem = "";
var quotesOpen = false;
for (int i = 0; i < inputString.Length; i++)
{
if (inputString[i] == '"')
{
quotesOpen = !quotesOpen;
continue;
}
if (inputString[i] == ',' && !quotesOpen)
{
itemList.Add(currentIem);
currentIem = "";
continue;
}
if (currentIem == "" && inputString[i] == ' ') continue;
currentIem += inputString[i];
}
if (currentIem != "") itemList.Add(currentIem);
return itemList;
}
示例测试用法:
var test1 = ItemStringToList("one, two, three");
var test2 = ItemStringToList("one, '"two'", three");
var test3 = ItemStringToList("one, '"two, three'"");
var test4 = ItemStringToList("one, '"two, three'", four, '"five six'", seven");
var test5 = ItemStringToList("one, '"two, three'", four, '"five six'", seven");
var test6 = ItemStringToList("one, '"two, three'", four, '"five six, seven'"");
var test7 = ItemStringToList("'"one, two, three'", four, '"five six, seven'"");
如果你想要更快的字符连接,你可以把它改成StringBuilder
试试这个,它可以用很多方法分割数组字符串,如果你想用空格分割,只要在(' ')中加一个空格。
namespace LINQExperiment1
{
class Program
{
static void Main(string[] args)
{
string[] sentence = new string[] { "apple", "orange", "baboons cows", " rainbow", "unicorns gummy bears" };
Console.WriteLine("option 1:"); Console.WriteLine("————-");
// option 1: Select returns three string[]’s with
// three strings in each.
IEnumerable<string[]> words1 =
sentence.Select(w => w.Split(' '));
// to get each word, we have to use two foreach loops
foreach (string[] segment in words1)
foreach (string word in segment)
Console.WriteLine(word);
Console.WriteLine();
Console.WriteLine("option 2:"); Console.WriteLine("————-");
// option 2: SelectMany returns nine strings
// (sub-iterates the Select result)
IEnumerable<string> words2 =
sentence.SelectMany(segment => segment.Split(','));
// with SelectMany we have every string individually
foreach (var word in words2)
Console.WriteLine(word);
// option 3: identical to Opt 2 above written using
// the Query Expression syntax (multiple froms)
IEnumerable<string> words3 =from segment in sentence
from word in segment.Split(' ')
select word;
}
}
}
这比我想象的要棘手,我认为这是一个很好的实际问题。
下面是我想到的解决方案。对于我的解决方案,我不喜欢的一点是必须在后面加上双引号,另一个是变量名:p:
internal class Program
{
private static void Main(string[] args)
{
string searchString =
@"apple, orange, ""baboons, cows. dogs- hounds"", rainbow, ""unicorns, gummy bears"", abc, defghj";
char delimeter = ',';
char excludeSplittingWithin = '"';
string[] splittedByExcludeSplittingWithin = searchString.Split(excludeSplittingWithin);
List<string> splittedSearchString = new List<string>();
for (int i = 0; i < splittedByExcludeSplittingWithin.Length; i++)
{
if (i == 0 || splittedByExcludeSplittingWithin[i].StartsWith(delimeter.ToString()))
{
string[] splitttedByDelimeter = splittedByExcludeSplittingWithin[i].Split(delimeter);
for (int j = 0; j < splitttedByDelimeter.Length; j++)
{
splittedSearchString.Add(splitttedByDelimeter[j].Trim());
}
}
else
{
splittedSearchString.Add(excludeSplittingWithin + splittedByExcludeSplittingWithin[i] +
excludeSplittingWithin);
}
}
foreach (string s in splittedSearchString)
{
if (s.Trim() != string.Empty)
{
Console.WriteLine(s);
}
}
Console.ReadKey();
}
}
另一个正则表达式解决方案:
private static IEnumerable<string> Parse(string input)
{
// if used frequently, should be instantiated with Compiled option
Regex regex = new Regex(@"(?<=^|,'s)('""(?:[^'""]|'""'"")*'""|[^,'s]*)");
return regex.Matches(inputData).Where(m => m.Success);
}