c#命令行代码可以工作，但winforms代码不行

本文关键字：代码 winforms 工作 命令行 | 更新日期: 2023-09-27 18:19:16

我正在制作一个Adobe Echosign演示c# winforms应用程序。我的代码是他们的命令行代码的直接副本(经过修改)，但是，我的代码在传输数据后返回一个错误。

这是EchoSign的命令行代码

public static void sendDocument(string apiKey, string fileName, string formFieldLayerTemplateKey, string recipient)
{
    FileStream file = getTestPdfFile(fileName);
    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new secure.echosign.com.FileInfo(fileName, null, file);
    SenderInfo senderInfo = null;
    string[] recipients = new string[1];
    recipients[0] = recipient;
    DocumentCreationInfo documentInfo = new DocumentCreationInfo(
        recipients,
        testPrefix + Path.GetFileName(file.Name),
        testMessage,
        fileInfos,
        SignatureType.ESIGN,
        SignatureFlow.SENDER_SIGNATURE_NOT_REQUIRED
    );
    if (formFieldLayerTemplateKey != null)
    {
        secure.echosign.com.FileInfo[] formFieldLayerTemplates = new secure.echosign.com.FileInfo[1];
        formFieldLayerTemplates[0] = new secure.echosign.com.FileInfo(formFieldLayerTemplateKey);
        documentInfo.formFieldLayerTemplates = formFieldLayerTemplates;
    }
    DocumentKey[] documentKeys;
    documentKeys = ES.sendDocument(apiKey, senderInfo, documentInfo);
    Console.WriteLine("Document key is: " + documentKeys[0].documentKey);
}

这是我的代码块，从他们的系统返回一个错误:

public static void sendDocument(string apiKey, string fileName, string formFieldLayerTemplateKey, string recipient)
{
    try
    {
        SenderInfo senderInfo = new SenderInfo();
        senderInfo = null;
        FileStream FileToSign = getTestPdfFile(fileName);
        byte[] bytes = System.IO.File.ReadAllBytes("C:''PROJECTS''TestFile.pdf");

        secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
        fileInfos[0] = new EchoSignTest.secure.echosign.com.FileInfo();
        fileInfos[0].fileName = fileName;
        fileInfos[0].mimeType = null;
        fileInfos[0].file = bytes;
        RecipientInfo[] docRecipient = new RecipientInfo[1];
        docRecipient[0] = new RecipientInfo();
        docRecipient[0].email = recipient;
        DocumentCreationInfo documentInfo = new DocumentCreationInfo();
        documentInfo.recipients = docRecipient;
        documentInfo.name = testPrefix + Path.GetFileName(FileToSign.Name);
        documentInfo.message = testMessage;
        documentInfo.fileInfos = fileInfos;
        documentInfo.signatureType = SignatureType.ESIGN;
        documentInfo.signatureFlow = SignatureFlow.SENDER_SIGNATURE_NOT_REQUIRED;
        if (formFieldLayerTemplateKey != null)
        {
            secure.echosign.com.FileInfo[] formFieldLayerTemplates = new secure.echosign.com.FileInfo[1];
            formFieldLayerTemplates[0] = new secure.echosign.com.FileInfo();
            formFieldLayerTemplates[0].formKey = formFieldLayerTemplateKey;
            documentInfo.formFieldLayerTemplates = formFieldLayerTemplates;
        }
        EchoSignDocumentService19PortTypeClient ES = new EchoSignDocumentService19PortTypeClient();
        DocumentKey[] documentKeys = new DocumentKey[1];
        documentKeys = ES.sendDocument(apiKey, senderInfo, documentInfo);
        Console.WriteLine("Document key is: " + documentKeys[0].documentKey);
    }
    catch (NullReferenceException ex)
    {
        string errMessage = ex.Message;
    }
    catch (Exception ex)
    {
        string errMessage = ex.Message;
    }
}

这两个代码块有什么不同?错误可能存在于FileInfo[]或DocumentCreationInfo()块中。我可能没有按照系统的要求创建对象。

c#命令行代码可以工作，但winforms代码不行

错误似乎是您读取到fileInfos[0].file变量的文档的字节的直接分配。在FileInfo的文档中指出，file参数必须是使用base64编码的原始文件内容，但是您分配原始文件内容时没有对其进行编码。当使用文件流调用构造函数时，就像第一个示例(命令行示例)一样，构造函数似乎会自动处理这个问题。您可以尝试在Winforms示例中更改这些行:

    FileStream FileToSign = getTestPdfFile(fileName);
    byte[] bytes = System.IO.File.ReadAllBytes("C:''PROJECTS''TestFile.pdf");

    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new EchoSignTest.secure.echosign.com.FileInfo();
    fileInfos[0].fileName = fileName;
    fileInfos[0].mimeType = null;
    fileInfos[0].file = bytes;

插入到代码中并尝试是否有效:

    FileStream FileToSign = getTestPdfFile(fileName);

    secure.echosign.com.FileInfo[] fileInfos = new secure.echosign.com.FileInfo[1];
    fileInfos[0] = new secure.echosign.com.FileInfo(fileName, null, FileToSign);

你应该使用提供的构造函数，而不是直接赋值，以确保所有的变量/参数都被正确处理。

您在关于构造函数的评论中告诉的错误可能是在构造函数调用之前的EchoSignTest.前缀的结果，因为这似乎是您自己的程序的名称空间，而不是所提供的API的正确名称空间。

相关文章：