如何从另一个Mdi子窗体显示(Bringtofront)已打开的Mdi子表单

本文关键字：Mdi 表单 Bringtofront 显示 另一个 窗体 | 更新日期: 2023-09-27 18:20:32

在我的应用程序中，我有4个表单，form1是一个mdi容器，其余的表单是它的子级，在form1中，我在加载事件中打开所有子窗体。在childform2中，我有一个将切换到childform3的按钮。我的问题是如何从childform2 中的按钮显示childform3（已经打开）

               form1:
               Form2 formchild1;
               Form3 formchild2;
               Form4 formchild3;
        private void Form1_Load(object sender, EventArgs e)
        {

        if (formchild2 == null)
        {
            formchild2 = new Form3();
        }
        formchild2.MdiParent = this;
        formchild2.Dock = DockStyle.Fill;
        formchild2.Show();
        //formchild2.BringToFront();

        if (formchild3 == null)
        {
            formchild3 = new Form4();
        }
        formchild3.MdiParent = this;
        formchild3.Dock = DockStyle.Fill;
        formchild3.Show();

        if (formchild1 == null)
        {
            formchild1 = new Form2();
        }
        formchild1.MdiParent = this;
        formchild1.Show();
        formchild1.Dock = DockStyle.Fill;
        formchild1.BringToFront();

        }

        form2:
        Form3 formchild2;
   private void button1_Click(object sender, EventArgs e)
    {
        //what i have to write hare..
            //formchild2 = new Form3();
            //formchild2.MdiParent = this.ParentForm;
            //formchild2.Dock = DockStyle.Fill;
            //formchild2.Show();
            //formchild2.BringToFront();
    }

如何从另一个Mdi子窗体显示(Bringtofront)已打开的Mdi子表单

当您创建form2时（请更改变量名，花了一段时间才发现formchild1实际上是form2），您需要实例化form2实例

if (formchild1 == null)
{
    formchild1 = new Form2(/*Either pass in a Form3 here*/);
}
formchild1.formChild2 = formchild2; //Or make formChild2 public member
formchlid1.SetForm(formChild2); //Or make a method that sets it
formchild1.MdiParent = this;
formchild1.Show();
formchild1.Dock = DockStyle.Fill;
formchild1.BringToFront();

然后再次显示，你可以只做

formchild2.BringToFront();

childform3 childform3=new childform3;
private void button1_Click(object sender, EventArgs e)
    {
        if (!childform3.IsDisposed)
            childform3.Select();
        else
            childform3= new frmSearch();
        childform3.MdiParent = ParentForm;
        childform3.Show();
    }
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