当jquery uploadify上传时,重命名httphandler中的文件
本文关键字:httphandler 重命名 文件 jquery uploadify | 更新日期: 2023-09-27 18:22:20
我想要通过httphanlder在ASP.Net中使用jQuery Uploadify进行多文件上传。
当不更改名称文件时,很好地工作并上传所有文件,当我想在httphandler中更改文件名时,许多文件不上传并中断。
asp.net代码为:
$("#<%=FileUpload1.ClientID %>").fileUpload({
'uploader': '../js/uploader.swf',
'cancelImg': '../images/cancel.png',
'buttonText': 'Browse Files',
'script': 'Upload.ashx',
'folder': '../FileUpload/AttachmentFiles/' + userID,
'fileDesc': 'Image Files',
'fileExt': '*.jpg;*.jpeg;*.gif;*.png',
'multi': true,
'auto': true,
'onUploadProgress': function (file, bytesUploaded, bytesTotal, totalBytesUploaded, totalBytesTotal) {
$('#progress').html(totalBytesUploaded + ' bytes uploaded of ' + totalBytesTotal + ' bytes.');
}
, onComplete: function (event, queueID, fileObj, response, data) {
debugger;
var onclick = 'FileDelete("' + queueID + '")';
var ul = $('#AttchmentFiles');
var li = '<li data-ID=' + queueID + '><a><img onclick=' + onclick + ' src="Template/Images/Remove.png" width="20" height="20" /></a><a><img src="' + response + '" width="30" height="30" style="top: 0;" /></a>';
ul.append(li);
}
});
httphandler文件代码:
public class Upload : IHttpHandler
{
public void ProcessRequest(HttpContext context)
{
context.Response.ContentType = "text/plain";
context.Response.Expires = -1;
try
{
HttpPostedFile postedFile = context.Request.Files["Filedata"];
string savepath = "";
string tempPath = "";
tempPath = HttpContext.Current.Request.QueryString["folder"];
savepath = context.Server.MapPath(tempPath);
string filename = FileName(postedFile);
if (!Directory.Exists(savepath))
Directory.CreateDirectory(savepath);
postedFile.SaveAs(savepath + @"'" + filename);
context.Response.Write(tempPath + "/" + filename);
context.Response.StatusCode = 200;
}
catch (Exception ex)
{
context.Response.Write("Error: " + ex.Message);
}
}
public string FileName(HttpPostedFile postedFile) {
string Extention = Path.GetExtension(postedFile.FileName);
string randstr = "";
if (Extention.ToLower() == ".jpg" || Extention.ToLower() == ".png" || Extention.ToLower() == ".jpeg" || Extention.ToLower() == ".gif")
{
Random rand = new Random();
int Intrandom1 = rand.Next(100000000, 999999999);
int Intrandom2 = rand.Next(100000000, 999999999);
int Intrandom3 = rand.Next(100000000, 999999999);
randstr = "Img" + Intrandom1.ToString() + Intrandom2.ToString() + Intrandom3.ToString() + ".jpg";
}
else if (Extention.ToLower() == ".fla" || Extention.ToLower() == ".mp4" || Extention.ToLower() == ".flv")
{
Random rand = new Random();
int Intrandom1 = rand.Next(100000000, 999999999);
int Intrandom2 = rand.Next(100000000, 999999999);
int Intrandom3 = rand.Next(100000000, 999999999);
randstr = "movie" + Intrandom1.ToString() + Intrandom2.ToString() + Intrandom3.ToString() + ".flv";
}
//'*.pdf;*.zip;*.rar;*.txt;*.docx',
else if (Extention.ToLower() == ".pdf" || Extention.ToLower() == ".zip" || Extention.ToLower() == ".rar" || Extention.ToLower() == ".txt" || Extention.ToLower() == ".docx")
{
Random rand = new Random();
int Intrandom1 = rand.Next(100000000, 999999999);
int Intrandom2 = rand.Next(100000000, 999999999);
int Intrandom3 = rand.Next(100000000, 999999999);
randstr = "file" + Intrandom1.ToString() + Intrandom2.ToString() + Intrandom3.ToString() + Extention.ToLower();
}
return randstr;
}
public bool IsReusable
{
get
{
return false;
}
}
}
这是因为以下内容将始终为每个文件生成相同的输出,这将导致所有文件都使用相同的文件名编写。第一个上传的文件会成功,但其余大部分文件在保存过程中都会失败,因为目标文件正在使用中,其中一些文件会成功但实际上会覆盖以前上传的文件。
Random rand = new Random();
int Intrandom1 = rand.Next(100000000, 999999999);
int Intrandom2 = rand.Next(100000000, 999999999);
int Intrandom3 = rand.Next(100000000, 999999999);
你为什么不改为:
randstr = "Img" + Guid.NewGuid().ToString() + ".jpg";
这是我的测试:
Random rand = new Random();
int Intrandom1 = rand.Next(100000000, 999999999);
int Intrandom2 = rand.Next(100000000, 999999999);
int Intrandom3 = rand.Next(100000000, 999999999);
Console.WriteLine("{0}{1}{2}", Intrandom1, Intrandom2, Intrandom3);
rand = new Random();
Intrandom1 = rand.Next(100000000, 999999999);
Intrandom2 = rand.Next(100000000, 999999999);
Intrandom3 = rand.Next(100000000, 999999999);
Console.WriteLine("{0}{1}{2}", Intrandom1, Intrandom2, Intrandom3);
以下是我的结果:
288925957582541325412731421
288925957582541325412731421