C#中数组中字符串的二进制搜索
本文关键字:二进制 搜索 字符串 数组 | 更新日期: 2023-09-27 18:25:05
好吧,所以我已经在这个错误上呆了大约18个小时,完全迷失了方向。我试图做的是进行二进制搜索,其中搜索从数组的中间开始,然后每次通过将搜索到的项与中间项进行比较来消除一半的数组。到目前为止,我的代码没有产生错误,除非我试图比较搜索到的术语是否大于中间术语。我知道我正在尝试比较两个字符串,所以大于不适用,但我不知道其他方法
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
string[] contacts = new string[20];
private void button1_Click(object sender, RoutedEventArgs e)
{
listBox1.Items.Clear(); //Clears the ListBox of all previous items
if (!File.Exists("Week3List.txt")) //Verifies that the file exists
{
MessageBox.Show("You need to write the file first", "Validation", MessageBoxButton.OK); //Notifies the user if the file does not exist
return;
}
using (StreamReader sr = new StreamReader("Week3List.txt")) //Designates the path to the file that was created
{
try
{
contacts = File.ReadAllLines("Week3List.txt");
Array.Sort(contacts);
foreach (string contact in contacts)
{
listBox1.Items.Add(contact);
}
sr.Close(); //Closes the StreamReader
}
catch (Exception ex) //A catch to handle access errors
{
MessageBox.Show(ex.ToString(), "Exception Handler", MessageBoxButton.OK); //Adds the error message to the ListBox
}
}
}
private void button2_Click(object sender, RoutedEventArgs e)
{
bSearch(contacts);
}
private void bSearch(string[] contacts)
{
int index = Array.BinarySearch(contacts, textBox1.Text);
}
public int BinarySearch(string[] contacts, string searchTerm)
{
int first = 0;
int last = contacts.Length - 1;
int position = -1;
bool found = false;
int compCount = 0;
searchTerm = textBox1.Text;
while (found != true && first <= last)
{
int middle = (first + last) / 2;
if (contacts[middle] == searchTerm)
{
found = true;
position = middle;
compCount++;
MessageBox.Show("Your search has been found after " + compCount + "comparisons.");
}
else if (contacts[middle] > searchTerm)
{
last = middle;
compCount++;
}
else
{
first = middle;
compCount++;
}
}
return position;
return compCount;
}
}
}
有人看到我哪里错了吗?或者知道一种方法可以将两者进行比较,以获得更大或更小的值吗?我想,因为它是排序的,它可能会比较第一个字母,并根据它来确定,但我错了。
只需使用List<T>.BinarySearch
方法。
List<String> myList = new List<String>{"Apple", "Microsoft", "Yahoo", "StackOverflow" };
myList.Sort(); //Apple Microsoft StackOverflow Yahoo
myList.BinarySearch("Yahoo"); // 3
或者如果使用Array
:
string[] myArr = new string[]{"Apple", "Microsoft", "Yahoo", "StackOverflow" };
Array.Sort(myArr); //Apple Microsoft StackOverflow Yahoo
Array.BinarySearch<string>(myArr, "Yahoo"); // 3
好的,感谢RegularExpression提出的研究字符串比较方法的建议。我更改了代码
if (contacts[middle] == searchTerm)
和else if (contacts[middle] > searchTerm)
至
CCD_ 5和CCD_ 6
它现在运行得很好!感谢大家的快速回复。
看看这个比较字符串的方法。它会告诉你一个字符串是大于、小于还是等于另一个字符串:
http://msdn.microsoft.com/en-us/library/zkcaxw5y%28v=vs.110%29.aspx
好吧,你试过了吗:
contacts.ToList().BinarySearch(searchTerm);
如果你想对字符串数组进行二进制搜索,这就是方法。你可能想为StringComparer选择一个不同的区域性。
string[] arr = {"a","b","c","d","e","f","g"};
int k = Array.BinarySearch(arr,"d",StringComparer.InvariantCulture);
如果您想在不使用内置编程语言的扩展和助手你应该这样做:(见在线演示)
重要提示:您的
Array
应该是sorted
,因为Binarry-Search
不在UnSorted
列表中工作。
static int Find(string[] data, string SearachItem)
{
//It is mandatory to turn off case-sensitive by convert values to lowercase or uppercase
ConvertArrayToLower(data);
string Lower = SearachItem.ToLower();
//initiate
char XChar = Lower[0]; // we will compare first char of Search Item by first char of array values
int FirstIndex = 0;
int LastIndex = data.Length - 1;
while (FirstIndex <= LastIndex)
{
int MiddelIndex = (FirstIndex + LastIndex) / 2;
char middel = data[MiddelIndex][0];
if (XChar > middel)
FirstIndex = MiddelIndex + 1;
else if (XChar < middel)
LastIndex = MiddelIndex - 1;
else if (data[MiddelIndex] != Lower) // maybe the first char of two or more values will be the same so we should go to the next step
{
FirstIndex = MiddelIndex + 1;
}
else return MiddelIndex; // if found
}
//if not found
return -1;
}
private static void ConvertArrayToLower(string[] data)
{
for (int i = 0; i < data.Length; i++)
{
data[i] = data[i].ToLower();
}
}
查看在线演示