使用MVC.Net5在一个调用中执行多个控制器操作

我们最近将代码库从.Net 4.0升级到.Net 4.5.1，并从MVC 2.0升级到MVC 5.2.2。

我们在基本控制器类中有一个自定义方法，它允许我们在一个请求中更新视图的多个部分。升级后，此功能不再有效。

原始代码：

protected void IncludeAction(string actionName, string controllerName, object routeValues)
{
    //Get Url
    RouteValueDictionary routes = null;
    if (routeValues != null)
        routes = new RouteValueDictionary(routeValues);
    else
        routes = new RouteValueDictionary();
    routes.Add("Action", actionName);
    if (!string.IsNullOrEmpty(controllerName))
        routes.Add("Controller", controllerName);
    else
        routes.Add("Controller", this.ControllerContext.RouteData.Values["Controller"].ToString());
    var url = RouteTable.Routes.GetVirtualPath(this.ControllerContext.RequestContext, routes).VirtualPath;
    //Rewrite path
    System.Web.HttpContext.Current.RewritePath(url, false);
    IHttpHandler httpHandler = new MvcHttpHandler();
    httpHandler.ProcessRequest(System.Web.HttpContext.Current);
}

我们在httpHandler.ProcessRequest调用中收到错误。我们在许多地方使用了这种技术。在谷歌上搜索了很多之后，我们似乎应该使用Server.TransferRequest。

新代码

protected void IncludeAction(string actionName, string controllerName, object routeValues)
{
    //Get Url
    RouteValueDictionary routes = null;
    if (routeValues != null)
        routes = new RouteValueDictionary(routeValues);
    else
        routes = new RouteValueDictionary();
    routes.Add("Action", actionName);
    if (!string.IsNullOrEmpty(controllerName))
        routes.Add("Controller", controllerName);
    else
        routes.Add("Controller", this.ControllerContext.RouteData.Values["Controller"].ToString());
    var url = RouteTable.Routes.GetVirtualPath(this.ControllerContext.RequestContext, routes).VirtualPath;
    //Rewrite path
    System.Web.HttpContext.Current.RewritePath(url, false);
    System.Web.HttpContext.Current.Server.TransferRequest(url, true);
}

当从这样的代码调用时：

IncludeAction("OptInBanner", "Person");
IncludeAction("NavMenu", "Person");
return Transfer(returnurl);

我们的新代码产生了这个错误：

Type:
    System.InvalidOperationException
Message:
    TransferRequest cannot be invoked more than once.
Stack Trace:
    at System.Web.HttpServerUtility.TransferRequest(String path, Boolean preserveForm)
    at MyProject.MyNamspace.MyBaseController.IncludeAction(String actionName, String controllerName, Object routeValues)
    at MyProject.MyNamspace.MyBaseController.IncludeAction(String actionName, String controllerName)
    at MyProject.MyNamspace.MyController.MyAction(Boolean myChoice, String returnurl)
    at .lambda_method(Closure , ControllerBase , Object[] )

由于消息明确表示我不能多次调用TransferRequest，但我的代码除了重定向和执行第三个操作外，还需要执行两个控制器操作，所以我想我应该恢复到旧代码。然而，这会产生这个错误：

Type:
    System.InvalidOperationException
Message:
    'HttpContext.SetSessionStateBehavior' can only be invoked before 'HttpApplication.AcquireRequestState' event is raised.
Stack Trace:
    at System.Web.Routing.UrlRoutingHandler.ProcessRequest(HttpContextBase httpContext)
    at MyProject.MyNamspace.MyBaseController.IncludeAction(String actionName, String controllerName, Object routeValues)
    at MyProject.MyNamspace.MyBaseController.IncludeAction(String actionName, String controllerName)
    at MyProject.MyNamspace.MyController.MyAction(Boolean myChoice, String returnurl)
    at .lambda_method(Closure , ControllerBase , Object[] )

对于这个函数，在使用较新的框架和MVC时，我如何在没有错误的情况下保留我们在.Net 4.0和MVC 2.0下的原始行为？

protected void IncludeAction(string actionName, string controllerName, object routeValues)
{
    string targetController = null;
    if (!string.IsNullOrWhiteSpace(controllerName))
    {
        targetController = controllerName;
    }
    else
    {
        targetController = this.ControllerContext.RouteData.Values["Controller"].ToString();
    }
    HtmlHelper htmlHelper = new HtmlHelper(
        new ViewContext(
            this.ControllerContext,
            new WebFormView(this.ControllerContext, actionName),
            this.ViewData,
            this.TempData,
            this.Response.Output
        ),
        new ViewPage()
    );
    htmlHelper.RenderAction(actionName, targetController, routeValues);
}