Castle Windsor-将Type作为构造函数参数传递

本文关键字：构造函数 参数传递 Type Windsor- Castle | 更新日期: 2023-09-27 18:28:26

我有一个类，它将Type作为构造函数参数。如何在Windsor集装箱中登记？

   public Class NLogLogger : ILogger
   {
      private NLog.Logger _logger;  
      public NLogLogger(Type type)
      {
           _logger = NLog.LogManager.GetLogger(type.FullName);
      }
    ...
   }

我正在尝试以这种方式注册：

            container.Register(Component.For(typeof(ILogger))
                                .ImplementedBy(typeof(NLogLogger))
                                .LifestyleTransient()
                                .DependsOn(new Hashtable
                                            {
                                                {"type", ???}
                                            }));

我需要填写???。我不知道如何将调用类的Type传递到那里。

Castle Windsor-将Type作为构造函数参数传递

更新

根据您的更新，您希望注入类型，以便可以使用它进行日志记录。有两种解决方案。

public class ClassDependentOnLogger
{
    private ILogger _logger;  
    public ClassDependentOnLogger(ILogger logger)
    {
        _logger = logger;
    }
    ....
}

1-使用Windsor SubDependencyResolver。下面的例子展示了如何返回ILog的实例，但如果你想这样做，你可以很容易地将其调整为返回Type：

public class LoggerResolver : ISubDependencyResolver
{
    private readonly IKernel kernel;
    public LoggerResolver( IKernel kernel )
    {
        this.kernel = kernel;
    }
    public object Resolve( CreationContext context, ISubDependencyResolver contextHandlerResolver, Castle.Core.ComponentModel model, DependencyModel dependency )
    {
        return NLog.LogManager.GetLogger(model.Implementation.FullName);
    }
    public bool CanResolve( CreationContext context, ISubDependencyResolver contextHandlerResolver, Castle.Core.ComponentModel model, DependencyModel dependency )
    {
        return dependency.TargetType == typeof( ILogger );
    }
}
//Register the sub dependency resolver. This looks cleaner if you do it via a
//Facility but that's a whole other class
Container.Kernel.Resolver.AddSubResolver( new LoggerResolver( Kernel ) );

2-使用Windsor LoggingFacility

不需要您的示例中描述的NLoggerClass。

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