RestSharp 反序列化不起作用

本文关键字：不起作用 反序列化 RestSharp | 更新日期: 2023-09-27 18:31:13

下面的原始输出（从 RestResponse.Content 属性获得）未被反序列化。 是因为"ns1"被添加为前缀吗？ 我做错了什么吗？

以下是进行调用时返回的原始 JSON 内容：

{"

ns1.model-response-list"：{"@throttle"："2"，"@total-models"："3372"，"ns1.model-re sponses"：{"ns1.model"：[{"@mh"："0x20e800"，"ns1.attribute"：{"@id"："0x1006e"，"$"："S servername.com"}}，{"@mh"："0x21a400"，"ns1.attribute"：{"@id"："0x100 6e"，"$"："servername.com"}}]}，"ns1.link"：{"@rel"："next"，"@href"：" http://ipaddress/spectrum/restful/devices?id=93fc1a07-60be-4dd5-964c-7 e8660dd3028&start=2&throttlesize=2"，"@type"："application/xml"}}}

class Program
{
static void Main(string[] args)
{
var client = new RestClient(Spectrum.Endpoints.Development);
client.Authenticator = new HttpBasicAuthenticator("myid", "mypassword");
var request = new RestRequest(Method.GET);
request.RequestFormat = DataFormat.Xml;
request.Resource = "devices?{attr}&{throttlesize}";
request.AddParameter("attr", Spectrum.Attributes.ModelName);
request.AddParameter("throttlesize", "2");
IRestResponse<ModelResponseList> response = client.Execute<ModelResponseList>(request);
Console.Write(response.Data.Throttle); // This line keeps returning 0, but should return 2
}

以下是应保存数据的类：

[DeserializeAs(Name = "model-response-list")]
public class ModelResponseList
{
    [DeserializeAs(Name = "throttle")]
    public int Throttle { get; set; }
    [DeserializeAs(Name = "total-models")]
    public int TotalModels { get; set; }
    [DeserializeAs(Name = "model-responses")]
    public List<Model> ModelResponses { get; set; }
    [DeserializeAs(Name = "link")]
    public Link Link { get; set; }
}
public class Model
{
    public string Mh { get; set; }
    public ModelAttribute Attribute { get; set; }
}
public class ModelAttribute
{
    public string Id { get; set; }
    public string Value { get; set; }
}
public class Link
{
    public string Rel { get; set; }
    // Note! Href must be escaped, e.g. "&" => "&amp;" or comment this prop out
    public string Href { get; set; }
    public string Type { get; set; }
}

RestSharp 反序列化不起作用

你应该通过NuGet获取 Json.NET，让它帮助你。它比RestSharp的内置反序列化更复杂。

Json.NET 后，可以使用下面的类对 JSON 进行反序列化。这一次，我希望您在收到答案后不要删除问题，而是接受并可能投票赞成？

所以，使用

var response = client.Execute(request);
var deserialized = JsonConvert.DeserializeObject<Wrapper>(response.Content);
Console.WriteLine(JsonConvert.SerializeObject(deserialized));

控制台的输出如下

{"

ns1.model-response-list"：{"@throttle"：2，"@total-models"：3372，"ns1.model-responses"：{"ns1.model"：[{"@mh"："0x20e800"，"ns1.attribute"：{"@id"："0x1006e"，"$"："Sservername.com"}}，{"@mh"："0x21a400"，"ns1.attribute"：{"@id"："0x1006e"，"$"："servername.com"}}]}，"ns1.link"：{"@rel"："下一步"，"@href"："hxxp://ipaddress/spectrum/restful/devices?id=93fc1a07-60be-4dd5-964c-7e8660dd3028&start=2&throttlesize=2"，"@type"："application/xml"}}}

如果您使用以下类

[JsonObject]
public class Wrapper
{
    [JsonProperty(PropertyName = "ns1.model-response-list")]
    public ModelResponseList ModelResponseList { get; set; }
}
[JsonObject]
public class ModelResponseList
{
    [JsonProperty(PropertyName = "@throttle")]
    public int Throttle { get; set; }
    [JsonProperty(PropertyName = "@total-models")]
    public int TotalModels { get; set; }
    [JsonProperty(PropertyName = "ns1.model-responses")]
    public Responses ModelResponses { get; set; }
    [JsonProperty(PropertyName = "ns1.link")]
    public Link Link { get; set; }
}
[JsonObject]
public class Responses
{
    [JsonProperty(PropertyName = "ns1.model")]
    public List<Model> Model { get; set; }
}
[JsonObject]
public class Model
{
    [JsonProperty(PropertyName = "@mh")]
    public object Mh { get; set; }
    [JsonProperty(PropertyName = "ns1.attribute")]
    public ModelAttribute Attribute { get; set; }
}
[JsonObject]
public class ModelAttribute
{
    [JsonProperty(PropertyName = "@id")]
    public string Id { get; set; }
    [JsonProperty(PropertyName = "$")]
    public string Value { get; set; }
}
[JsonObject]
public class Link
{
    [JsonProperty(PropertyName = "@rel")]
    public string Rel { get; set; }
    [JsonProperty(PropertyName = "@href")]
    public string Href { get; set; }
    
    [JsonProperty(PropertyName = "@type")]
    public string Type { get; set; }
}
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