使用来自具有非标准名称的 REST API 的 JSON 响应
本文关键字:REST API 响应 JSON 非标准 | 更新日期: 2023-09-27 18:33:02
{"balances-and-info":{"on_hold":[],"available": {"USD":0.93033384},"usd_volume":"243.18","fee_bracket": {"maker":"0.00","taker":"0.60"},"global_usd_volume":"0.09942900"}}
我有这个 JSON 响应,我正在尝试将其存储在一个对象中,但是如您所见,"余额和信息"不能用作变量名称。我一直使用的方法是:
RestClient client = new RestClient("http://currency-api.appspot.com/api/");
RestRequest request = new RestRequest(url);
var response = client.Execute<Currency>(request);
Currency obj = response.Data;
显然上课要容易得多
public class Currency
{
public string rate { get; set; }
}
那么我该如何处理呢?
String.replace() 用 balances_and_info 平衡和信息
在您的代码中
YourObject deserialized = parseResponse(obj.replace("balances-and-info", "balances_and_info"));
YourObject parseResponse(string response) {
try
{
// https://www.nuget.org/packages/Newtonsoft.Json/
// Json.NET
YourObject ret = JsonConvert.DeserializeObject<YourObject>(response);
return ret;
}
catch (JsonSerializationException)
{
// do something
}
return null;
}
您的对象
使用 http://json2csharp.com/并生成对象(复制响应字符串,将余额和信息替换为balances_and_info并生成)
public class Available
{
public double USD { get; set; }
}
public class FeeBracket
{
public string maker { get; set; }
public string taker { get; set; }
}
public class BalancesAndInfo
{
public List<object> on_hold { get; set; }
public Available available { get; set; }
public string usd_volume { get; set; }
public FeeBracket fee_bracket { get; set; }
public string global_usd_volume { get; set; }
}
public class YourObject
{
public BalancesAndInfo balances_and_info { get; set; }
}