需要一些 C# 的重载信息
本文关键字：重载 信息 | 更新日期: 2023-09-27 18:34:23
im 在以下方面遇到问题，想看看是否有人可以帮助我。 详细信息在代码中，但是我试图重载构造函数并且参数名称给了我一个错误：
using system
//blah, blah blah
class Animal
{
private string name;
private string race;
private double _weight;
private double _age;
public Animal(string n,string r, double a, double w)
{
name = n;
race = r;
age = a;
weight = w;
}
public double age
{
get
{
return _age;
}
set
{
if (value > 0 && value <= 25)
{
_age = value;
}
else
{
do
{
Console.WriteLine("Invalid Age!'nDog's age: " + value);
Console.Write("Please enter dog's age: ");
age = double.Parse(Console.ReadLine());
} while (_age < 0 && age > 25);
}
}
}
public double weight
{
get
{
return _weight;
}
set
{
if (value > 0 && value <= 60)
{
_weight = value;
}
else
{
do
{
Console.WriteLine("Invalid Weight!'nDog's weight: " + value);
Console.Write("Please enter dog's weight: ");
weight = double.Parse(Console.ReadLine());
} while (_weight < 0 && _weight >= 60);
}
}
}
public Animal()
{
Console.WriteLine("Invalid Age!" + "'nInvalid Weight!");
Console.Write("'nInformation for the 1st dog : ");
getdetails();
}
public void info()
{
Console.Write("'nInformation for the 2nd dog: ");
Console.WriteLine("'nName: " + name + ", Race: " + race
+ ", Age: " + age + ", Weight: " + weight);
Console.ReadLine();
}
public void getdetails()
{
_age = 1;
_weight = 1;
Console.WriteLine("'nName: No Name, Race: No Race" + ", Age: " + _age + ", Weight: "
+ _weight);
Console.WriteLine();
}
public static void Main(String[] args)
{
Animal dog = new Animal();
Animal dog2 = new Animal(name,race,age,weight);***//HERE'S THE ERROR!
//SO HERE ARE WHERE MY TROUBLES LIE. I CREATED A NEW OBJECT AND I AM TRYING TO PASS
THE ENTERED INFORMATION FROM THE USER TO ONE OF MY CONSTRUCTORS BUT
IM HAVING A TOUGH TIME DOING IT. COULD SOMEBODY HELP PLEASE?***
Console.Write("Please enter your dog's name: ");
dog.name = Console.ReadLine();
Console.Write("Please enter your dog's race: ");
dog.race = Console.ReadLine();
Console.Write("Please enter your dog's age: ");
dog.age = double.Parse(Console.ReadLine());
Console.Write("Please enter your dog's weight: ");
dog.weight = double.Parse(Console.ReadLine());
dog.info();
}
}
}
现在我知道有很多东西不必写在这个代码中，但这就是我应该这样做的方式，我只是在参数方面遇到问题，请帮忙吗？
您似乎混淆了构造函数调用和函数调用 ->
animal(name, race ...)只是代码中的一个函数，因此您无法直接调用它。 看看如何重载构造函数。 顺便说一句，很高兴知道您使用的是哪种语言^^
抱歉，我正在用我的C++帽子分析您的代码...在 C# 中，除了将正确的值作为参数传递之外，您所做的一切都是正确的。您正在尝试在定义/分配它们之前传递值，这就是您收到错误的原因。因此，对于 dog2，您可能希望这样做。
public static void Main(String[] args)
{
//variable declation
string name, race;
double age, weight;
//variable assigned user inputs
Console.Write("Please enter your dog's name: ");
name = Console.ReadLine();
Console.Write("Please enter your dog's race: ");
race = Console.ReadLine();
Console.Write("Please enter your dog's age: ");
age = double.Parse(Console.ReadLine());
Console.Write("Please enter your dog's weight: ");
weight = double.Parse(Console.ReadLine());
// call of the overloaded constructor with the right parameters
Animal dog2 = new Animal(name,race,age,weight);
dog2.info();
}
我希望这有帮助，祝你好运:)
您的示例有两个Constructors，一个默认的无参数Constructor，Animal()和一个需要四个参数Animal(string n, string r, double a, double w)的Constructor。 Constructor的签名会通知您预期parameter(s)的数量和type。
Animal dog = new Animal();
上述方法毫无怨言地工作，因为您使用的是默认的无参数构造函数。
Animal dog2 = new Animal(name, race, age, weight);
上述方法不起作用，因为您尝试使用参数化构造函数，但是，您以 unresolved symbols 的形式乱码传递它。
你需要做的是声明(如果需要，实例化(一些将传递给构造函数的变量：
public static void Main(string[] args)
{
string name = "SomeName";
string race = "SomeRace";
double age = 12;
double weight = 9001;
Animal dog2 = new Animal(name, race, age, weight);
}
如果您需要/希望用户定义传递给参数化构造函数的参数值，则需要执行类似于示例中进一步收集用户输入的方式(使用 Console.ReadLine()(。
*编辑：*
@"那你到底是什么意思，因为我确实声明了字符串和双变量来传递它们，但它不起作用。
您的那段代码似乎被省略或遗漏了。
@"你说我必须在类动物的构造函数中要求用户输入？或者创建一个接受输入以更改传递的变量值的方法？
您正在尝试使用 Main 函数内的参数化构造函数创建 Animal 的实例，因此您需要在进行构造函数调用之前和 Main 函数内部声明并实例化将用作Animal构造函数参数的变量。
确实声明了字符串和双精度，但我没有为它们分配值，因为就像你说的那样，我试图让用户定义我的参数，但我不确定如何准确做到这一点。">
您的代码已经有一个示例，说明如何获取用户输入并将其分配给变量：
// You wrote this [:
Console.Write("Please enter your dog's name: ");
dog.name = Console.ReadLine();
Console.Write("Please enter your dog's race: ");
dog.race = Console.ReadLine();
Console.Write("Please enter your dog's age: ");
dog.age = double.Parse(Console.ReadLine());
Console.Write("Please enter your dog's weight: ");
dog.weight = double.Parse(Console.ReadLine());
上述请求使用Console.ReadLine()的用户输入，然后将用户输入的值分配给关联的Animal property。 所以例如：
dog.name = Console.ReadLine();
以上假设已经有一个名为 dog 的Animal的有效实例。 dog有许多公共properties(name、race、age和weight). The left side (左操作数) of the赋值运算符( = ) is the object property that you want to assign a value to. The right side (右操作数) of the赋值运算符is where that value is derived. This could be Console.ReadLine(( (as in this example), a mathematical calculation or a hard coded value etc. However the右操作数is derived, it is to the左操作数'赋值。 这是你的任务。
再比如：
private static void Main(string[] args)
{
// Obtain parameter values from user
Console.WriteLine("Enter a name");
string name = Console.ReadLine();
Console.WriteLine("Enter a race");
string race = Console.ReadLine();
Console.WriteLine("Enter an age");
// Console.ReadLine() reads values in as strings
// Therefore you will need to convert the values you want as doubles
double age;
while (!double.TryParse(Console.ReadLine(), out age))
{
Console.WriteLine("The value you entered is not a valid age, please enter a valid age");
}
Console.WriteLine("Enter a weight");
double weight;
while (!double.TryParse(Console.ReadLine(), out weight))
{
Console.WriteLine("The value you entered is not a valid weight, please enter a valid weight");
}
// Create an instance of Animal
Animal dog2 = new Animal(name, race, age, weight);
}