使用字符串获取对象属性
本文关键字:取对象 属性 获取 字符串 | 更新日期: 2023-09-27 18:36:25
ca我在这里看到了几个反思的例子,但似乎无法让它们为我的确切问题工作......
我看过的解决方案示例
我的3节课...
public class Row
{
public string Cell1 = "cat";//{ get; set; }
public string Cell2 = "fish"; //{ get; set; }
public string Cell3 = "dog"; //{ get; set; }
}
public class Grid
{
public Row Row1 = new Row();
public Row Row2 = new Row();
public Row Row3 = new Row();
}
public class SetOfGrids
{
public Grid g1 = new Grid();
public Grid g2 = new Grid();
}
我如何获得价值...
SetOfGrids sog = new SetOfGrids();
MessageBox.Show(sog.g1.Row1.Cell1);
我认为链接的 getproperty 函数可能有效...
public Object GetPropValue(String name, Object obj) {
foreach (String part in name.Split('.')) {
if (obj == null) { return null; }
Type type = obj.GetType();
PropertyInfo info = type.GetProperty(part);
if (info == null) { return null; }
obj = info.GetValue(obj, null);
}
return obj;
}
我想如何获得价值...(我收到空异常错误。
string PathToProperty = "sog.g1.Row1.Cell1";
string s = GetPropValue(PathToProperty, sog).ToString;
MessageBox.Show(s);
结果应为"cat2"
更新将行代码更改为建议的以下内容。
public class Row
{
public string Cell1 { get; set; }
public string Cell2 { get; set; }
public string Cell3 { get; set; }
public Row()
{
this.Cell1 = "cat";
this.Cell2 = "dog";
this.Cell3 = "fish";
}
}
这个:
using System;
using System.Linq;
using System.Net;
using System.Reflection;
namespace Test
{
public class Row
{
public string Cell1 { get; set; }
public string Cell2 { get; set; }
public string Cell3 { get; set; }
}
public class Grid
{
public Row Row1 { get; set; }
public Row Row2 { get; set; }
public Row Row3 { get; set; }
}
public class SetOfGrids
{
public Grid g1 { get; set; }
public Grid g2 { get; set; }
}
class Program
{
public static object GetPropValue(string name, object obj)
{
foreach (string part in name.Split('.'))
{
if (obj == null) { return null; }
var type = obj.GetType();
var info = type.GetProperty(part);
if (info == null) { return null; }
obj = info.GetValue(obj, null);
}
return obj;
}
public static void Main()
{
SetOfGrids sog = new SetOfGrids
{
g1 = new Grid { Row1 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row2 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row3 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" } },
g2 = new Grid { Row1 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row2 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" }, Row3 = new Row { Cell1 = "cat", Cell2 = "fish", Cell3 = "dog" } }
};
string PathToProperty = "g1.Row1.Cell1";
object s = GetPropValue(PathToProperty, sog);
Console.WriteLine(s);
Console.ReadLine();
}
}
}
工作正常。请注意,我将所有字段更改为实际属性并删除了字符串的第一部分,因为"sog."是变量名称,而不是属性。
问题是你要求方法GetProperty来获取字段,而不是属性。尝试将字段更改为属性或使用 GetField 方法。