Opensearchserver API with C#

我/正在开发一个winforms c#应用程序，并希望在我的应用程序中使用openSearchServer API。您能否提供一些示例来说明如何为我的搜索获取 JSON/XML 响应？我目前正在使用以下方法，但可以提高效率

WebRequest request = WebRequest.Create("http://localhost:9090/select?use=MSG&login=lorem&key=08762e43getye0042f875e86eaiu687f&qt=search&q="+searchTerm );
        string responseFromServer = GetQueryResults(request);
        // Parse XML Data
        string response = GetResultsFromXML(responseFromServer);
   private string GetQueryResults(WebRequest request)
    {
        //specify protcol
        request.ContentType = "application/json";
        //request.Headers.
        request.Method = "PUT";
        ////Get Request stream
        Stream datastream = request.GetRequestStream();

        datastream.Close();
        // Get response
        WebResponse respose = request.GetResponse();
        datastream = respose.GetResponseStream();
        StreamReader reader = new StreamReader(datastream);
        string responseFromServer = reader.ReadToEnd();
        return responseFromServer;
    }
    private string GetResultsFromXML(string responseFromServer)
    {
        StringBuilder output = new StringBuilder();
        #region XmlDocument
        XmlDocument xdoc = new XmlDocument();

        xdoc.LoadXml(responseFromServer);

        XmlNodeList nodelist = xdoc.SelectNodes("/response/result/doc");
                    foreach (XmlNode node in nodelist)
        {
            DataGridViewRow dgvRow = (DataGridViewRow)dgvResults.Rows[0].Clone();
            foreach (XmlAttribute attrib in node.Attributes)
            {
                if (attrib.Name == "score")
                {
                    dgvRow.Cells[0].Value = attrib.Value;
                }
                else if (attrib.Name == "docId")
                {
                    dgvRow.Cells[1].Value = attrib.Value;
                }
                else if (attrib.Name == "pos")
                {
                    dgvRow.Cells[2].Value = attrib.Value;
                }
            }
            XmlNodeList elements = node.SelectNodes("snippet");
            foreach (XmlNode node_element in elements)
            {
                if (node_element.Attributes[0].Value == "title")
                {
                    dgvRow.Cells[3].Value = node_element.InnerText;
                }
            }
            dgvResults.Rows.Add(dgvRow);
        }
        #endregion


        return output.ToString();
    }

此外，该请求是使用 OpenSearchServer API 版本 1 发出的，因为我无法让 API2 工作。任何示例查询都会有所帮助，因为我找不到任何工作示例。

还尝试执行文档中给出的示例（版本 2 API）：

http://localhost:9090/services/rest/index/my_index/document?login=lorem&key=08762e43getye0042f875e86eaiu687f

它抛出一个 http 405 - 方法不允许错误。 我正在寻找实现opensearchserver的restful JSON API。在现有代码中（尝试使用返回 XML 的 API 版本 1）任何想法？？