如何在MVC3中使用MvcPaging2.0使用RouteValues
本文关键字:MvcPaging2 使用 RouteValues MVC3 | 更新日期: 2024-09-20 19:10:54
Html helper @Html.Pager
来自MvcPaging 2.0。有.Options(o => o.RouteValues(object RouteValues))
,它可以将Model返回给Controller,但MvcPaging要求此helper在其居住的View中填充IPagedList<model>
。这是生成表和分页的Model。实现mvcpage2.0的最佳方式是什么。使用SearchModel进行搜索,使用Model显示结果?
示例:
型号:
public class SearchModel
{
public string FirstName { get; set; }
public string LastName { get; set; }
}
public class Person
{
[Key]
public int Id { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public DateTime Dob { get; set; }
public string City { get; set; }
}
视图:索引.cshtml
@using (Ajax.BeginForm("Search", "SearchPerson", new AjaxOptions
{
HttpMethod = "GET",
InsertionMode = InsertionMode.Replace,
UpdateTargetId = "main_search_result_table_id"
}))
{
@Html.TextBoxFor(m => m.FirstName)
@Html.TextBoxFor(m => m.LastName)
<input type="submit" value="Search"/>
}
<div id="main_search_result_table_id">
@{Html.RenderPartial("_InitPartialEmpty");}
</div>
_ResultPartial.chtml
@using MvcPaging
@model IPagedList<Models.Person>
<table>
@foreach (var p in Model)
{
<tr>
<td>@p.FirstName</td>
<td>@p.LastName</td>
<td>@p.Dob</td>
<td>@p.City</td>
</tr>
}
<table>
@Html.Pager(Model.PageSize, Model.PageNumber,
Model.TotalItemCount, new AjaxOptions
{
UpdateTargetId = "main_search_result_table_id"
}).Options(o => o.RouteValues(Model)) //==> IPagedList<Models.Person>
控制器
public ActionResult SearchPerson(int? page,SearchModel person)
{
List<Person> result= adapter.GetPersons(person);
int currentPageIndex = page.HasValue ? page.Value - 1 : 0;
return PartialView("_ResultPartial",
result.ToPagedList(currentPageIndex, 10, result.Count()));
}
问题是如何使用搜索模型来实现MvcPaging2.0?或者还有其他更好的方法,可以进行复杂的搜索,而不使用模型来传递数据查询吗?有什么想法吗?
我正在使用MvcPaging 2.0,文档
编辑:*
谢谢Darin的回答,但我设法做到了:
*_ResultPartial.cshtml*
@Html.Pager(Model.PageSize, Model.PageNumber,
Model.TotalItemCount, new AjaxOptions
{
UpdateTargetId = "main_search_result_table_id"
}).Options(o => o.Action("AjaxPaging"))
控制器
public ActionResult SearchPerson(int? page,SearchModel person)
{
IQueryable<Person> query= adapter.GetPersons(person);
Session["SearchQuery"] = query;
int currentPageIndex = page.HasValue ? page.Value - 1 : 0;
List<Person> persons = query.ToList();
return PartialView("_ResultPartial",
persons.ToPagedList(currentPageIndex, 10, persons.Count()));
}
public ActionResult AjaxPaging(int? page)
{
IQueryable<Person> query = Session["SearchQuery"] as IQueryable<Person>;
int currentPageIndex = page.HasValue ? page.Value - 1 : 0;
List<Person> persons = query.ToList();
return PartialView("_ResultPartial",
persons.ToPagedList(currentPageIndex, 10, persons.Count()));
}
您可以编写一个自定义扩展方法,该方法将获取所有查询字符串参数,并将它们添加到页面链接中,此外还有所有currentPage、pageNumber、totalItemCount等。。。材料:
public static class PagerOptionsBuilderExtensions
{
public static PagerOptionsBuilder AddFromQueryString(
this PagerOptionsBuilder builder,
HttpRequestBase request
)
{
foreach (string item in request.QueryString)
{
builder.AddRouteValue(item, request.QueryString[item]);
}
return builder;
}
}
然后:
.Options(o => o.RouteValues(Model).AddFromQueryString(Request))