C# 中的 2D 数组到表

本文关键字：数组 2D 中的 | 更新日期: 2024-11-07 14:36:04

我需要将此表中的数据放入数组中，然后在控制台中使数组打印为格式化表。这是我从 http://puu.sh/oqV8f/7d982f2665.jpg 获得数据的表格;我只需要使数组输出行和列而不是列表。到目前为止，我有这个：

 using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace Zumba1
{
    class Zumba
    {
        static void Main(string[] args)
        { //Recreated the data in the table for the zumba section, added each row, and each column.
            string[,] schedule = new string [8, 6] { { "1:00", "3:00", "5:00", "7:00", "TOTAL", "", },
                                 {"Monday", "12", "10", "17", "22", "244",   },
                                 {"Tuesday", "11", "13", "17", "22", "252",},
                                 {"Wednesday", "12", "10", "22", "22", "264",},
                                 {"Thursday", "9", "14", "17", "22", "248",},
                                 {"Friday", "12", "10", "21", "12", "220",},
                                 {"Saturday", "12", "10", "5", "10", "148"},
                                 {" ", " ", " ", " ", " ","1376",}};
            foreach (string i in schedule)
            {
                Console.WriteLine(i.ToString());
            }
            Console.ReadKey();
        }
    }
}

有什么想法吗？

C# 中的 2D 数组到表

Foreach 在 [，] 数组上将所有元素作为一个列表，正如你所注意到的。在这种情况下，您需要输出如下：

for (int x0 = 0; x0 < schedule.GetLength(0); x0++)
{
    for (int x1 = 0; x1 < schedule.GetLength(1); x1++)
    {
        Console.Write("{0}'t", schedule[x0, x1]);
    }
    Console.WriteLine();
}
Console.ReadKey();

如果出于任何原因要使用foreach，还可以将表声明为 [][] 数组。但是在这两种方式中，您都必须创建 2 个循环： 

string[][] schedule = new string[][] {
                                    new string[] { "1:00", "3:00", "5:00", "7:00", "TOTAL", "", },
                                    new string[] {"Monday", "12", "10", "17", "22", "244",   },
                                    new string[] {"Tuesday", "11", "13", "17", "22", "252",},
                                    new string[] {"Wednesday", "12", "10", "22", "22", "264",},
                                    new string[] {"Thursday", "9", "14", "17", "22", "248",},
                                    new string[] {"Friday", "12", "10", "21", "12", "220",},
                                    new string[] {"Saturday", "12", "10", "5", "10", "148"},
                                    new string[] {" ", " ", " ", " ", " ","1376",}
        };
foreach (string[] line in schedule)
{
    foreach (string i in line)
        Console.Write("{0}'t", i);
    Console.WriteLine();
}

如果您在控制台中使用等宽字体，则可以根据需要通过放置更多空格来调整每个事物的显示位置

例如，对于对应于第 1 行和第 2 行以及第二列第 1 列的成员，这将是要计算的事情：

最大的单词是星期三，即 9 个字母，在第一行第一列我应该放置 9 个空格，因为会有空白。然后，您可以在列之间放置四个空格作为分隔符，然后对于第二列，您计算出 1：00 是最大的字符串，因此对于 12，您将添加 2 个额外的空格，依此类推。

使用制表符而不是一些空格也可能有效，但如果表格最终有一些字符串比另一列中的字符串大得多，它将不起作用。

希望对您有所帮助。

知道了。

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace Zumba1
{
    class Zumba
    {
        static void Main(string[] args)
        { //Recreated the data in the table for the zumba section, added each row, and each column. Worked on formatting.
            string[,] schedule = new string[8, 6] { { "'t't1:00", "3:00", "5:00", "7:00", "TOTAL", "", },
                                 {"Monday", "'t12", "10", "17", "22", "$244",   },
                                 {"Tuesday", "'t11", "13", "17", "22", "$252",},
                                 {"Wednesday", "12", "10", "22", "22", "$264",},
                                 {"Thursday", "9", "14", "17", "22", "$248",},
                                 {"Friday", "'t12", "10", "21", "12", "$220",},
                                 {"Saturday", "12", "10", "5", "10", "$148"},
                                 {" ", " ", " ", " ", " ","'t$1376",}};
            //Nested for loops to print in a table-style format.
            for (int i = 0; i < schedule.GetLength(0); i++)
            {
                for (int j = 0; j < schedule.GetLength(1); j++)
                {
                    Console.Write(schedule[i, j] + "'t");
                }
                {
                    Console.WriteLine(i.ToString());
                }
            }
     Console.ReadLine();
            }
        }
    }
}
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