如何从MySQL中选择sum(max remain(x+y+z))来捕获sum(1200+1300+1400)

本文关键字：sum 1200+1300+1400 x+y+z max MySQL 选择 remain | 更新日期: 2023-09-27 18:03:15

如何选择sum(max remain(x + y + z)) from MySQL，以捕获sum(1200+1300+1400) ?

id | user | remain
-----------------
1  | x   | 1000
----------------
2  | x   | 1200
----------------
3  | y   | 1100
----------------
4  | y   | 1300
----------------
5  | z   | 1200
----------------
5  | z   | 1400
----------------
using (SqlConnection cn = new SqlConnection(Class1.x))
        {
            cn.Open();
            string cm1 = "select sum(max remain(all users)) as 'total' from item_new_company";
            using (SqlCommand cmd = new SqlCommand(cm1, cn))
            {
                using (SqlDataReader dr = cmd.ExecuteReader())
                { dr.Read(); tot5 = dr["total"].ToString(); }
            }
        }

像这样:

SELECT SUM(MaxRemain) TotalOfMaxRemains
FROM
(
    SELECT MAX(remain) AS MaxRemain
    FROM item_new_company
    GROUP BY user
) AS t;

SQL Fiddle Demo

结果:

| TOTALOFMAXREMAINS |
---------------------
|              3900 |

子查询:

SELECT MAX(remain) AS MaxRemain
FROM item_new_company
GROUP BY user

对于GROUP BY user和MAX(remain)，

将为每个user提供remain的最大值，然后在外部查询中SUM将为您提供总数。

更新

对于SQL Server，前面的查询应该可以正常工作，但是还有另一种方法:

WITH CTE AS
(
  SELECT *, ROW_NUMBER() OVER(PARTITION BY [user] 
                              ORDER BY id DESC) AS rownum 
  FROM item_new_company 
) 
SELECT SUM(remain) AS Total 
FROM CTE 
WHERE rownum = 1;