如何在NUNIT中使用[TestCase]或[TestCaseSource]传递结构参数给测试函数
本文关键字:结构 参数 函数 测试 TestCaseSource NUNIT TestCase | 更新日期: 2023-09-27 18:07:39
我现在在实践TDD。我想通过使用[TestCase]或[TestCaseSource]属性来简化我糟糕的测试功能。请帮帮我。这是我现在的函数
[Test]
public void GetLength_TEST_1()
{
double output = Program.GetLength(new Point { x = 1, y = 2 }, new Point { x = 7, y = 8 });
output *= 1000;
output = Math.Truncate(output);
output /= 1000;
Assert.AreEqual(8.485, output);
}
[Test]
public void GetLength_TEST_2()
{
double output = Program.GetLength(new Point { x = 2, y = 7 }, new Point { x = -8, y = -6 });
output *= 1000;
output = Math.Truncate(output);
output /= 1000;
Assert.AreEqual(16.401, output);
}
使用TestCaseSource属性。
注意相同的测试方法应该执行两个测试用例。
如下所示
[TestFixture]
public class MyClass
{
public class PointTestCase
{
public string TestName { get; private set; }
public Point P1 { get; set; }
public Point P2 { get; set; }
public double Result { get; set; }
public PointTestCase(Point p1, Point p2, double result)
{
P1 = p1;
P2 = p2;
Result = result;
}
public override string ToString()
{
return TestName;
}
}
private static IEnumerable<PointTestCase> PointTestCases
{
get
{
yield return new PointTestCase(new Point { x = 1, y = 2 }, new Point { x = 7, y = 8 }, 8);
yield return new PointTestCase(new Point { x = 2, y = 7 }, new Point { x = -8, y = -6 }, -12);
}
}
[Test, TestCaseSource("PointTestCases")]
public void GetLength_TEST(PointTestCase pointTestCase)
{
double output = Program.GetLength(pointTestCase.P1, pointTestCase.P2);
output *= 1000;
output = Math.Truncate(output);
output /= 1000;
Assert.AreEqual(pointTestCase.Result, output);
}
}
public static class Program
{
public static double GetLength(Point p1, Point p2)
{
//some logic/calculation
return p1.x * p2.y;
}
}
public class Point
{
public double x { get; set; }
public double y { get; set; }
}